2.Since there are only two categories, the confidence interval for either category can beconstructed from its proportion. The proportion for “not hard” is 0.696, so that p = 0.696and q = 1 – p = 1 – 0.696 = 0.304. Suppose a 95% confidence interval is to beconstructed, so that the z value is 1.96. Therefore, the margin of error ME can becalculated as ME = z *√p(1−p)n= 1.96 *√0.696×0.3041243= 0.0256. Therefore,the lower bound is 0.696 – 0.0256 = 0.6704 and the upper bound is 0.696 + 0.0256 =0.7216. Therefore, in terms of percentage the 95% confidence interval for the category“not hard” is (67.04%, 72.16%). Similarly for the category “hard” the lower bound is0.304 – 0.0256 = 0.2784 and the upper bound is 0.304 + 0.0256 = 0.3296. Therefore, interms of percentage the 95% confidence interval for the category “hard” is (27.84%,32.96%).3.It means that if many such identical samples are taken then the population mean of thepercentage for the category “not hard” will be between 67.04% and 72.16% in 95% ofthose samples, while the population mean of the percentage for the category “hard” willbe between 27.84% and 32.96% in 95% of those samplesPart 2 (20 POINTS)1.For variable wwwhr “[Respondent] use WWW hours per week) (donotrecode the variable) –produce the most appropriate SPSStableandgraph.