EC1 lab write up.docx - VI-1 Resistor A Resistor B Resistor...

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VI-1) Resistor A Resistor B Resistor C Resistor D V R (Volts) 3.775 5.471 9.813 12.369 I(mA) 25 25 25 12.5 R DMM (Ω) 163.62 225.4 388.2 982.1 R calculated (Ω) 151 218.84 392.52 989.52 σ R =+ 1 Ω R A + σ R = 3.775/.0250 = 151 Ω R B + σ R = 5.471/.0250 = 219 Ω R C + σ R = 9.813/.0250 = 393 Ω R D + σ R = 12.369/.0125 = 990 Ω None of the calculated values fall within the DMM range. VI-2) # V (volts) I (mA) 1 0.77 5 2 1.52 10 3 2.262 15 4 3.01 20 5 3.765 25 0 5 10 15 20 25 30 0 0.5 1 1.5 2 2.5 3 3.5 4 f(x) = 0.15x + 0.02 V vs. I I (mA) V (Volts) Using Linest: S+ σ S = 0.1496 + 0.00024 kΩ Since S=R R+ σ R = 0.1496 + 0.00024 kΩ
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The resistor is an ohmic conductor because it increases linearly, it does not increasingly change with varying current. It obeys the equation R=V/I. 0 5 10 15 20 25 30 35 40 0 0.1 0.2 0.3 0.4 0.5 0.6 0.7 0.8 V (Volts) I (mA) V (Volts) VI-3) # V (Volts) I(mA) 1 0.2 0 2 0.4 0 3 0.6 1 4 0.65 4 5 0.7 11 6 0.71 14 7 0.72 18 8 0.73 23 9 0.74 29 10 0.75 37 R .60 = V/I = .6/1 = .600 kΩ R .65 = V/I = .65/4 = .1625 kΩ R .70 = V/I = .70/11 = .0636 kΩ The diode is not an ohmic conductor because the resistance does not obey the equation R = V/I, it also does not increase linearly. VI-4) R series V (Volts) 8.727 I (mA) 5
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R series (Ω) 1181. 5 Calculated from above data: R S + σ RS = V/I + .001 = 5.69/3.55 + .001 = 1.7454 + .001 kΩ Calculated from VI-1: R S = R 1 + R 2 + R 3 + R 4 = 151 + 219 + 393 + 990 = 1753 Ω σ RS = ((.001) 2 + (.001) 2 + (.001) 2 + (.001) 2 ) 1/2 = .002 kΩ R S + σ RS =1753 + 2 Ω The resistance calculated from VI-4 is more accurate than the value calculated from VI-1 data. The
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  • Fall '17
  • Resistor, Electrical resistance, ohmic conductor

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