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IMG_20160214_125201.jpg - A Given Specific enthalpy of...

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Unformatted text preview: A Given: Specific enthalpy of Fluid entering the nozzle = 30ook Jkah Specific enthalpy of fluid leaving the nozzle= 2762kykazha Velocity of Fluid entering the nozzle = Vi=60muls From thermodynamics It law we have 9-W= 4KE+OPE+4h 40-0 =(V -VP) +Cha-h() -> x (v."-ve)- hi-ha - V-V - 2 (hy-hz) Vi-(Go) - 2(3000-2162) VA = 3600 +476 : N1. V2 - J4076 V2 = 63.84 ms -- Velocity at He exit of nozzle = 63-8Hm/s 3A) Given Pi= lam Pa PA-20k Pa 9 = ro.29KJs ha = 2512KJ(kg 419h = 1 hi =2 785 KJ7kg m =0- wakes V2 100MIS VI = 33 .33 w /s Ha-0M He. = 3me...
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