140Bquiz7csols - ( , 3) , ( 3 , 0) , (0 , 3) and ( 3 , )...

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1 MATH 140B QUIZ#7 Solutions Version A Due: Mon Oct 22, 2007 1. i) False . The domain is the set of all real numbers. ii) True . f ( x ) = f ( x ) . iii) True . lim x →∞ f ( x ) = 0 . Therefore, D) is the answer. 2. i) True . The factor 1 x 2 (and hence f ) is positive for all x ( 1 , 1) . ii) True . The factor 1 x 2 (and hence f ) is negative for all x ( −∞ , 1) (1 , ) . iii) True . By the information in parts i) and ii) and Frst derivative test. Therefore, E) is the answer. 3. i) True . Set the numerator of f ′′ ( x ) = 0 and solve. It is already factored. ii) False . f ′′ takes on the sign , + , , + on the 4 intervals
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Unformatted text preview: ( , 3) , ( 3 , 0) , (0 , 3) and ( 3 , ) respectively. iii) False . In view of the comment in ii), there are exactly 3 points of inection. Therefore, A) is the answer. 4. The correct graph is B). 5. i) False . The vertical asymptote is at x = 4 / 3 . ii) False . The horizontal asymptote is at y = 2 / 3 . iii) False . The graph is not symmetric about the origin since f ( x ) n = f ( x ) . . Therefore, E) is the answer....
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This note was uploaded on 03/30/2008 for the course MATH 140B taught by Professor Fabbri,marc during the Fall '07 term at Pennsylvania State University, University Park.

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