HW4 solution (1).pdf - husband Solution Ca > For Determine...

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Unformatted text preview: husband Solution Ca > For Determine find I suitable Km , and , C L A -31 H Rounding up washer . Table ⇒ 8-7 Table Table 44 Td = 8-2 8 ⇒ -8 Kb L ⇒ = H is % = in . in 1275 . Ae Ld CE It 1/4=2LE Zdt LT - =3 . 69 30.0 3 - = a = 0.1419 = 4.25 = 0544 Ate E in in Ad Let IT = , have we , 32 - = Ld - . A- Ad At E =L Ld 4 = 4.25 = ⇒ thus , height nut = Kb Lte Ad L . in 0.095 3-69+76 , 18-131 ; from Table , 210,09-57=369 the , = Kb Find bolt the . is t as It Lt for - table 3 fasteners and length thickness 2T = From Eq a washer the • W IN American Standard plain For • Kb Screws 4 H in . 69 3 in in ? npsi . . = in 1963 RR for 0Y963Cal4l9# 146 691 to 0.1963 Co 1,25 - o 44=1.25 steel =/ ' 479 Mbf / in • Find km . steal 1if washer ! - - : ! Em - - - - ' ⑦ ETo ② I. ' . . - . ⑤ . . . . it in ← . - - For two Ki KG = 075 DIE ke C Table in - - -4=0.095 . -317 A Gilts = In Dtd tt Tickle 5) ) co . 14.5 same -531 - d 0.095 ) Stiffness Mpsf -531 in . ) ) I -10-75-105317 C 1415 ) 0-421096725 = Coit 43.11 - 0.5311 Mlbfllh - 0.304568775 = - . dea , - thickness in the in - - - 9632104226 In . CD T.is#3CEIt3ll United = E= . 0.095 have they , . - - - - washer §DttDd 0-5774 - - . . Ed 57747 a ka find , I - washer iron case - . - - i i & - - - , Isin i. . steel thickness in k¥2 ¥117 = t t in - - . a 0.095 Kf CTabA32 ) & Kz +2=1.75 ⇒ Doe F- Kz = C t - o - , or 86 as ) - Mlbffin 27.81 = C - HI in do , = tan 300 I of in = 30 . mpsi , 2.592in = 0.5774 Kz - " Dz T.is#cTEta- 92¥57 M¥529 =n÷a In - (0-25)+2,592+0.5 lilt ⇒ 0.860+210.5 D4= 0.57741T = in 44=1 C , doe ) Ean - 38=1.437 ( at E= , - in (1.437-05) His mpsi in 13.1512 = t 1.437+051 4155 ) . ' in as 1415 ) OS # LY in aaa . . & Kc, 0-5 1307 IT = ( µ ) -860+05 o -13=0.25 ⇒ 2475 in 21725 1. & Kz lilt ) 21 , -3¥ in . - in 27 Dzt in 300=01860 tan 26,0957 t as 05774713030,52 = Cliffs Dz= , npsi 30 = 075 de in =3 9,197 4,052204 - 2.0897204 mlbflin K5⇒ * t-s-o.es As ↳ in 0.86 = ds . in in as - - 27.21 . 0-5774*139051 In KJ ( htt In ) as 08Gt t C 0,86 as - ) 45.11 = kin ¥ = o = Sp = 40 = km Kip Recommended preload Spae NL = Fi . - . 8-9 Table Mbf 0-6975 Mlbfllh . 0.75 = go Tp = = At . AX ' . 1419 Spite box - o 1629×8=3.26657 o a = Tp O Kip 87 for grade Spat . =¥=8 D= o.rs Fi 1629 a = 45¥ + 1in 479 Nets . 39747 t 7.60 = ¥+2 = kpsic 120 km 1. Kbt Petal (b) 1315 . 679%5 + ⇒ KI C= • 2¥ 437ft = - that # too II tis + ¥ = Sc⇒t¥ = npsi 30 E= . - 1419 in ' np Spat = Fi opt = 12020,14291 0,1629×81-0.75×120291429 - p CI = - bae 84 I Per pmox Oa ccpmax 0.1629 ) 920489 . Kip P - I - apt Pnm ) - ZAC can ccpmoxt = The Sue - + of - Se Tat Sue of - Com og . ) - = 8-9 Table 8-17 Sue , , Se Oi = = =ccptr ZAC ) I , Sueoatsecomoi Table - fatigue failure without P maximum ) - ) - = Selfie ⇒ . ZAL Sec ht Pnm ) -2 ZAL = # = - Pmn=¥=2 . 210658 - = d = (c) , 0.75×12020,1429 Fi No I = to 23.2 kpsi kpsi . → ht ⇒ . Sec Sue oil - Sue = Sue Cpt ) c Se Ite €¥ec p Sue C C 2 = Sue Ae Se CSue P to = CC 2 1- ( Sue Sec +2 it Sp ) o - Sue - t Se - C ( ) Sue - Se ) C Set t ZAE Sp ) 0.7T Sp ) - APHIS se at - Sec Sue At ) CPH ) Sec t or - + 2 - = Se Con t Sue = ⇒ Oa -0.164 - ( 0-75×1207+0.1629 0.1419632 = to to ) C = 77 . 3 2 98 . Kip - 150+23-2 ) 23-2 Ctso ) ...
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  • Spring '09
  • NagarajArakere
  • Trigraph, Sue C

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