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# 20190322_012345.jpg - BEC(1 C YEA and so by definition of...

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Unformatted text preview: @ ) BEC (1 ) C YEA, and so by definition of intersection, XEBNA` This B-ASBRAS b )_ . But given any element in A that element is in C) (because) A ( B ) and so that element is also in_d) ( [email protected]) ). Have show that A CC we must show that every Element in a) is in * GB and YEAR - 8.4 than by defaultion of Compliment a REB And KEA. Proof : Suppose A , B , and I are sets and A LB and BEC. TO REB and X EA. But then by definition of campimmut , * EBB and and so by definition of set difference, X ED- A . This BAA'S B- A` 3 ) The following is a proof that for all sets A, B, and C_ if B - A S BAA"\ Sqex XEB - A. By definition of sex difference. BOA'C BS- A SIMOSE X E BRAC. By definition of intersection` 5) Prove that for all sets` A and B. ( B- A ) = BOAS C ) B A CB and B CC , the ACC Fall in the blanked\ b ) C Proof : Supose A) and BS are Sets by definition of sub set definition of Sub set A CC . a ) A 16.2...
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• Fall '19
• NoProfessor
• B-ASBRAS, definition of intersection

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