F5114F8B-5172-4B78-9501-8DE0C0238189.png

# F5114F8B-5172-4B78-9501-8DE0C0238189.png - u'=ov'=(ax 49...

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Unformatted text preview: u'=ov'= (ax 49) Ox4 12 dx (+(w)) = fYu) . u V'= 3x3 (2x349)-1/2 + (x ) = 3 (ax-5) 7/3. (2) f(x )- o(12xa ) - (4) (3x" (2x 344)'h) 3(ax-s)t's 2 of 2 (Jax 549 or - lax ? ( 2x349)2 2 x 34 9 - or 3 3 (2x-S) 2 5) f (x) = sec(3x) Sx ( seex ) = Secx tanx Mflu) ) = flu).u 6) y = cot-3x Jx (f(u))=f lu). u' (cotx)-3 5 ((4x ) = -(50% f'(x)= Sec( 3x) tan( 3x) . 3 y'= - 3 ((Gix) . (-csex) 3sec(ex ) tan( 3x) y = 3csco cot X 7) f (x) = 10sin? (x) Jx ( Sinx ) = Cosy 8) f (x) = = CSC2(3x) dix (csex)= -(sox(oly (flu))= f (u).u' (esc(31)) x (S(u)) = f/4.).u f (x)- 16 (asin(x) . cosx) f\(x) = a use(ex ). (-(su(ax) col ( 3)). 3 20 sinx Losx = -(csc( Ex) CSC(3x)cot/3x or -(csc'(3x) (01(3x) 9) Find the equation of the line tangent to the graph of y = 2sinx at the following x-values: a) x1 =z b) x,=; y.= asin 1'= 2 (0)=0 y . = 2sin ( W/4) - & (3/2)= 2 y'=2 cosx y'- 2 cost m= 2 cos i = 2 (-1)= -2 m= acos (W/4) -205)) = Va y-0=-a (x-NY) y- Ja= Ja (x- D/4) 10) Write the equation of the normal line to the graph y = (2x + 1)3 at x =-1. Im-7naq Rip y1 = (a(-1)+1) 3 y'= 3 (x+1)' a = (-1) 3 y's b (2x+1)3 :-1 m= ((al-1)+s) = ((-1) ? =L y-()= -t(x-(-I)) Im= -To...
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• Fall '16
• Ms. Grieco
• Christopher Nolan, The Normal, Los Angeles International Airport, f lu, equation of the line tangent

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