# FD7C7098-69DD-4254-A895-640BCC643AD9.png - m= \$2-y H-a...

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Unformatted text preview: m= \$2-y: - H-a 12 -X1 2-1 3) Use the definition of the derivative to find the instantaneous rate of change of f (x) = -3x2 + 4 at x = 2 of 2 Slim -wxh-3hy fix ) = lim -3(xsh)' +4 - (-3x* +4) h-0 n20 = um -(x-3h h-70 = lim -3x*-uxh - 3h 44 +3x2-4 n =-Ux-3/0) ('(-a)--L(-a) f'(x) =-(x =1a 4) Find the equation of a tangent line to the function f (x) = (x2 + 2x) (x - 5) at the point (1, -12) y-y,=m(x-x1) y-(-Ia)= -13(x-1) W= 2x+3 x, yi (ub +w.V.") v'= 1 y+la=-13(x-1) filx)=(2x2) (x-5) +(x42x)() m= f' ()= (au)+2) (i-s)+ (12:(()X ) = (4X(-4)+(3)(1) = 213 1 to tangent Rino 5) Find the equation of a normal line to the function f (x) = 4x- -6x + 5 when x,= 2. y - yi= Jm (x-x, ) filx )= la x 2- (o ( using pouer row ) f'la)= la (a)-6 = 42 =m -> Im= m= " Ha y-25= - to (x-2) f (a) = 4(a):-((a)+S= aS=y, Directions: For #6 - 9, calculate the indicated derivative. 6) Find @, when y = -3x' -2x +7 du- -qx2 2 7) Given f (x) = 3x5 - 4x-* + 2x-3 - 2x, find f" (x). f'(x)= 15x +16X-S_(x-4 S "(x) = Lox3 80x +aux 8) [5x3 - 2x2 - 2x]x - -2 = 15x24x-2 x:2 = 15 (-a)e-4(-a) -2 - 60+8-2 U= 9) Find f ' (x), when f (x) = (3x-3 + 2x) (2Vx) V'=1x 5 - J Product eute u' .vtu.v' f (x) = (-qx * +a)(aux) + ( 3x *+ 2x ) (iz)...
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