WhatsApp Image 2019-03-29 at 10.19.07 PM.jpeg

# WhatsApp Image 2019-03-29 at 10.19.07 PM.jpeg - \5 To Find...

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Unformatted text preview: \5\\ To Find_ the Points where the_Curve has a horizontal_ tangent line _ _dys dyl do_ dx /do = 0 dy Fle) Sin (A ) + F 10 ) copp) d x F ( A ) COs ( D ) _ F (@ ) sin ( b ) < =\ FQ ) = 5 CSC(DL = _ Sun( D ) FIA ) - 5 Cos(D ) sin = ( D ) 5_ Cos(D )_ siAter_ Cos(D) dy since + Sin?(@) O 5 -- Sin ( A ) X P - 5 cos ( A )_ Cosle)_ sin? ( D) Sin CAL 5 COS ( D ) + 5 COS ( Q) - O sin A sing - 5 Cos (0 ) sing + 5 Cos ( 4 ) Sin ( D) = Q Sins ( Q ) - 5 Cos ( Q ) Sin ( 6 ) + 5 Cos ( D ) = Q - 5 toslot- (1 - 5ing ) = 0 _5 {es( 4) = 6 L_ since) _ Of # = It 3 TT T 2) D = [ 7 So the Points are Scanned_ with Cam Scanner...
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• Spring '08
• KijuwaIthink
• Trigraph, #, 6 l, toslot

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