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Unformatted text preview: Tutorial 7 : laminar and turbulent flow Covers week 6 and 7 lecture material Elger / Crowe et al Chapter 10 Problem ] A liquid is pumped through a \$60 - mm- diameter pipe at a flow rate of 0. 0002 m' / s. Calculate the pressure drop in a 10 - m horizontal section if the liquid is :` ( 2 ) SAE - LOW oil at 20 0 ( b ) Water at 20 0 ( C ) Glycerine at 40 0 0 ( 51 kPa , Re = 127 , laminar ; 0.5 kPa , Re = 13000 , not laminar ; 153 kPa , Re = 42, laminar ) V = Q/ A = 0. 00.02 1 (* * 0. 01 2 ) = 0. 637 m/s. = PUB = uscity 2 ) AD = SHIVL 8 X 0. 1 X 0. 637 * 10_^ - = 51000 Pa . Re = 127 - Laminar 0. 01 - b ) AD = SHIVL 8 x 1 x 10-3 X 0. 637 X 10` 0. 01 - - = 510 Pa . Re = 13000 - Not laminar C ) Ap = SHIVL _8 ( 0. 3 ) ( 0. 637 ) ( 10 )| To ( 0. 01 ) 2 ~ =| 153 000 Pa| Re = 42 - Laminar `) No . Flow is not laminar for water at room temperature , a plausible scenario . Problem 2 Consider flow with discharge Q = 0. 12 L's through an ID 8 mm smooth pipe . Find the flow regime ( laminar or turbulent ), and the friction factor using the Moody diagram when the a ) fluid is air at 35% C , and b ) fluid is water at 50%C. Discuss differences . ( 2 : laminar , \$= 0.055; 6: turbulent , \$ - 0. 023 ) Re - UD = kinematic visucity N First find the mean velocity ! = = =_ { a) For air at 35%( with _ _ = 1. 65 x 10^m' /'s we get the Reynolds number R =`_ \You , which indicates Laminar flow ( R X 2 x 10'). Hence , 1 = = = 0.055 b ) For water at sorc with `.. = \$. 53 x 10^m' I's we get the Reynolds number R =` _, which indicates turbulent flow ( 1 5. 3 * 10' for smooth pipes ). From Moody diagram , too two significant figures, we get / # 0.023....
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