Chp3_txtp70

Chp3_txtp70 - Notes to accompany lecture on p. 70 of text....

Info iconThis preview shows pages 1–2. Sign up to view the full content.

View Full Document Right Arrow Icon

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: Notes to accompany lecture on p. 70 of text. Case I. Consider a block of mass, M, falling through a height, h, ideally into a bath of water at temperature, T1. By ideally, we mean no splashing, wave generation or other energy wastes. If M = 1kg, T 1 = 298K, h = 3.0 m and C(bath) = 4.0 J/K, calculate T 2 , the final temperature of the bath. E block = Mg z = Mg ( z f- z i ) = Mg (0- h ) = - Mgh E bath = q + w = q + = C bath T E tot = E block + E bath = E block = - E bath C bath T = - (- Mgh ) = + Mgh T = 1.0 kg ( 29 9.8 m / s 2 ( 29 3.0 m ( 29 4 J / K = 7.4 K T 2 = 305.4 K Case II. Now block M, falling the same distance as in case I (and thereby having the same change in potential energy) now lifts a lighter block of mass, m, up a height, h (same distance through which M falls). If m = 500g = 0.50 kg, calculate T 2 . Note that we will use sys to denote block, M, as the system to distinguish it from block, m, which is part of the...
View Full Document

Page1 / 2

Chp3_txtp70 - Notes to accompany lecture on p. 70 of text....

This preview shows document pages 1 - 2. Sign up to view the full document.

View Full Document Right Arrow Icon
Ask a homework question - tutors are online