Unformatted text preview: Slope = R H ∆and intercept = R S ∆ Thus, if rxn is endothermic, slope is negative. As T increases (or 1/T decreases), ln K increases thus favoring the products. If rxn is exothermic, slope is positive. As T increases, ln K decreases thus favoring reactants. Consider this when working Problem 5 of WA Q09....
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 Fall '07
 Warren
 Chemistry, Thermodynamics, wA, RT ln

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