Unformatted text preview: Slope = R H ∆-and intercept = R S ∆ Thus, if rxn is endothermic, slope is negative. As T increases (or 1/T decreases), ln K increases thus favoring the products. If rxn is exothermic, slope is positive. As T increases, ln K decreases thus favoring reactants. Consider this when working Problem 5 of WA Q09....
View Full Document
This note was uploaded on 03/30/2008 for the course CH 201 taught by Professor Warren during the Fall '07 term at N.C. State.
- Fall '07