Unformatted text preview: Let us make 55mL of solution (to allow for the fact that, as we shall see, we’ll be using some of it). To make 55mL of 0.01M solution, ( 29 ( 29 ( 29 ( 29 stock mL x M mL M mL x 5 . 5 01 . 55 1 . = = Now, take the 0.01M solution as the new “stock” to make 55mL of 0.001M solution: ( 29 ( 29 ( 29 ( 29 stock M of mL x M mL M mL x 01 . 5 . 5 001 . 55 01 . = = As you see, we make 55mL of each more dilute solution, then use 5.5 mL of that, to make the next more dilute member of the set. There is a means to calculate the amounts needed “exactly” but this simplistic example helps to make the case....
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- Fall '07
- Chemistry, Solvent, ml, ml Final volume