EAS3434 Aero Struc I Ch03 (2018 09 30).pptx

EAS3434 Aero Struc I Ch03 (2018 09 30).pptx - Chap 3 Shear...

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Chap. 3: Shear stress distribution (6 hrs) Shear in straight members Shear formula Shear flow in built-up members 1
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2 3. Learning Outcomes At the end of this chapter, we should be able to:- Explain the existence of shear stress in a straight structural member based on an infinitesimal small element. Tell the shear stress distribution shape and locate the point of maximum shear stress. Relate shear flow in built-up members with the appropriate number of fastener.
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3 3. Shear in straight members There must be a force which resist the sliding of boards when they are bonded together. The force is called the shear force.
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4 3. Shear in straight members In this chapter, we will examine the behaviour of a beam in response to an internal shear force loading. Previously, we learnt that:
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5 3. Shear in straight members Consider a beam subjected to transverse loading: If we take a section, we could expect internal shear force V and internal bending moment M. If we isolate the section, we will find another pair of internal reactions.
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6 3. Shear in straight members To be exact, there is a slight difference of internal bending moment distribution due to the shear force: Hopefully this is not a surprise to you. Recall from the bending moment and shear force diagrams, we know that the rate of change of bending moment is the shear force. So there must be a slight difference of bending moment due to shear.
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7 3. Shear in straight members Due to bending moment, there is a normal stress (sigma) distribution at the left of beam element, and a similar normal stress distribution at the right, with a slight difference of delta sigma.
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8 3. Shear in straight members Due to internal shear force V, we could expect shear stress (tau) distribution on the left and right of the element.
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