# Stats - Chap. 10 Answers - 4 a. F test = 500/100=5 F...

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Review chapter 10 answers 1. a) Reject H(0) at the .05 level Completed ANOVA table: Source SS df MS ------ -- -- -- Between 30.5 4 7.625 Within 134.5 95 1.416 Total 165.0 99 F test statistic = 7.625 / 1.416 = 5.385 F α =0.05, df =4, 95 = 2.45 Decision rule : reject the null if F > 2.45 Conclusion : 5.385 > 2.45. Reject the null: not all the population means are equal. 2. d) 5 samples of size 9. n = 45 and c = 5, we have five treatments groups. You need to view the degrees of freedom: c-1, n-c. 3. F test = 15.3. F critical with α =0.05, df =4,40 =2.61 Decision rule : reject the null if F > 2.61 Conclusion : reject the null: not all means are equal.

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Unformatted text preview: 4 a. F test = 500/100=5 F critical =0.05, df =2, 12 = 3.89 Decision rule : reject if F &gt; 3.89 Conclusion : reject the null: the means are not all equal. Which shelving policies are different? T = q (=0.05, df= 3, 12) * SQRT (MSE/nj) =3.77 * SQRT (100/5) = 16.85 b. The absolute difference between the group means: We have 3 comparisons: c(c-1)/2 = 3*2 / 2 = 3 MIDDLE TOP = 10 MIDDLE BOTTOM = 20 TOP BOTTOM = 10 Only MIDDLE BOTTOM = 20 &gt; 16.85 so the difference between these means sales are statistically different. 5. c. 6. b. 7. d. 8. c. 9. b. 10. c. 11. d....
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## This note was uploaded on 03/30/2008 for the course STATISTICS 3001 taught by Professor Mcnertney during the Spring '08 term at TCU.

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Stats - Chap. 10 Answers - 4 a. F test = 500/100=5 F...

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