CHM 139 - Norman - Exam II

CHM 139 - Norman - Exam II - (Circle one) I give my...

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(Circle one) I give my permission for the public return of this exam. YES NO Chemistry 139 Name (printed) Exam 2 100 points Signature Fall 2007 Student Number Useful?: density of water = 1.00 g/mL P 1 = X 1 P 1 o (P + (n 2 a/V 2 ))(V – nb) = nRT R = 0.0821 L . atm/mol . K = 8.314 J/mol . K; P tot = Σ P i 1 atm = 760 torr K = 273 + o C Δ T f,b = K f,b m c π = M c RT P gas = k H M gas k H = 29 atm/M for CO 2 in water; For H 2 O: K b = 0.52 K/m c ; K f = 1.86 K/m c ; density = 1.00 g/mL; specific heat of liquid = 4.184 J/g•K Δ H (fus) = 6.008 kJ/mol; Δ H (vap) = 44.02 kJ/mol; specific heat of solid, 2.092 J/g•K k = Ae -Ea/RT ; ln k = ln A - Ea/RT; If N = A/B, then log N = log A - log B [A] = [A] 0 - kt; 1/[A] = kt + 1/[A] o ; ln[A] = ln[A] o - kt; t 0.5 = [A] 0 /2k; t 0.5 = 0.693/k; ln k 2 k 1 = E a R 1 T 1 - 1 T 2 x = - b ± b 2 - 4ac 2a t 0.5 = 1/k[A] 0 If N = A b , then log N = b log A Multiple choice (2 pts ea.) PLACE THE BEST ANSWER IN THE SPACE PROVIDED!!! 1. Molality is defined as . (A) moles of solute in 1 liter of solution (B) grams of solute in 1 liter of solvent (C) moles of solute in 1 kg of solvent (D) grams of solute in 1 kg of solvent (E) moles of solute in 1 liter of solvent (F) grams of solute in 1 liter of solution (G) moles of solute in 1 kg of solution (H) grams of solute in 1 kg of solution (I) number of children in 1 chemist’s family (J) the number of industrial spies at Dupont 2. When the vapor pressure of a liquid equals the external pressure, the liquid . (A) freezes (B) boils (C) sublimes (D) condenses (E) disappears (F) apparates
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CHM 139 - Norman - Exam II - (Circle one) I give my...

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