STATIC LAB 2 report.docx - UNIVERSITI TEKNIKAL MALAYSIA...

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DISEDIAKAN UNTUK: PN. SITI NOR’AIN BT MOKHTAR UNIVERSITI TEKNIKAL MALAYSIA MELAKA FTKMP LAB REPORT BMMA 1333 – STATICS SEMESTER 2, SESSION 2018/2019 LAB 1: EQUILIBRIUM OF FORCES FOR 4 POINT LOAD COURSE : 1 BMMA NAME STUDENT ID SECTIO N JIVEN RAJA A/L SILVARAJA B091810041 S1/1 MUHAMMAD HILMI BIN ZAINUDIN B091810265 S1/1 SUHAIL AZMIN BIN ROSMAN B091810313 S1/1 THARANEETHARAN A/L THAMBIRAJAH B091810476 S1/1
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PART A: THEORETICAL WORK TASK 1 1. Equilibrium of particle using resolution of forces method y Net Force at A F B ΣF = 0 F D F B + F C + F D = 0 x ΣF x i + ΣF y j = 0 ΣF x = F B cos30 ° - F D = 0 ΣFy = F B sin 30 ° - F C = 0 F C 2. Random Error = | CalculatedValue Measured Value Calculated Value | x 100%
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TASK 2 Figure 2.1: FBD at point A
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TASK 3 1. Equation of forces in X and Y direction: ΣF = 0 F B + F C + F D = 0 ΣF x i + ΣF y j = 0 ΣF x = F 1 cos θ 1 + F 2 cos135 ° + F 3 cos225 ° + F 4 cos315 ° ΣF y = F 1 sin θ 1 + F 2 sin 135 ° + F 3 sin 225 ° + F 4 sin315 °
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2. Example calculation: m 3 = 150g, m 4 = 150g F 3 = 150g x 10 -3 F 4 = 150g x 10 -3 = 0.15kg x (9.81) = 0.15kg x (9.81) = 1.47 N = 1.47 N At θ 1 = 0 ° ΣF x = F 1 + F 2 cos135 ° + F 3
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