HW2 Solutions

# HW2 Solutions - Homework Solutions ECE302 Spring 2007 HW 2...

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Unformatted text preview: Homework Solutions ECE302 Spring 2007 HW 2 1 2.7 v n = - m n E = - 700 cm 2 V- s 2500 V cm = - 1.75 x 10 6 cm s v p = + m p E = + 250 cm 2 V- s 2500 V cm = + 6.25 x 10 5 cm s j n = - qnv n = - 1.60 x 10- 19 C ( 29 10 17 1 cm 3 - 1.75 x 10 6 cm s = 2.80 x 10 4 A cm 2 j p = qnv p = 1.60 x 10- 19 C ( 29 10 3 1 cm 3 6.25 x 10 5 cm s = 1.00 x 10- 10 A cm 2 2.14 For intrinsic silicon, s = q m n n i + m p n i ( 29 = qn i m n + m p ( 29 s ≥ 1000 Ω- cm ( 29- 1 for a conductor n i ≥ s q m n + m p ( 29 = 1000 Ω- cm ( 29- 1 1.602 x 10- 19 C 100 + 50 ( 29 cm 2 v- sec = 4.16 x 10 19 cm 3 n i 2 = 1.73 x 10 39 cm 6 = BT 3 exp- E G kT with B = 1.08 x 10 31 K- 3 cm- 6 , k = 8.62x10-5 eV/K and E G = 1.12 eV This is a transcendental equation and must be solved numerically by iteration. This is a transcendental equation and must be solved numerically by iteration....
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HW2 Solutions - Homework Solutions ECE302 Spring 2007 HW 2...

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