HW6_Solutions

# HW6_Solutions - Homework Solutions HW 6 ECE302 Spring 2007...

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Homework Solutions ECE302 Spring 2007 HW 6 1 4.1 (a) V G > V TN corresponds to the inversion region (b) V G << V TN corresponds to the accumulation region (c) V G < V TN corresponds to the depletion region 4.10 a ( 29 0 < 1 V cutoff region, I D = 0 b ( 29 1V= 1V cutoff region, I D =0 (c) V GS - V TN =1 V , V DS = 0.1 V triode region I D = K n ' W L V GS - V TN - V DS 2 V DS = 250 m A V 2 10 m m 1 m m 2 - 1 - 0.1 2 0.1 (29 =+ 231 m A (d) V GS - V TN =2 V , V DS = 0.1 V triode region I D = K n ' W L V GS - V TN - V DS 2 V DS = 250 m A V 2 10 m m 1 m m 3 - 1 - 0.1 2 0.1 (29 =+ 488 m A e (29 K n = K n ' W L = 250 m A V 2 10 m m 1 m m = 2.50 mA V 2 4.18 Picking two values in saturation : 395 m A = K n 2 4 - V TN ( 29 2 and 140 m A = K n 2 3 - V

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HW6_Solutions - Homework Solutions HW 6 ECE302 Spring 2007...

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