HW10_Solutions

HW10_Solutions - Homework Solutions HW 10 14.102 M1 : ID =...

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Homework Solutions ECE302 Spring 2007 HW 10 1 14.102 M 1 : I D = 0.01 2 V GS + 2 ( 29 2 | V GS =- 9000 I D V GS =- 1.80 V I D = 0.01 2 - 1.8 + 2 ( 29 2 = 200 m A | V DS = 15 - 15 k Ω+ 9 k ( 29 I D = 10.2 V g m = 2 10 mA / V 2 ( 29 0.2 mA ( 29 = 2 mS | r o = 50 + 10.2 ( 29 V 0.2 mA = 301 k Q 2 : V EQ 2 = 15 43 k 43 k Ω+ 160 k = 3.18 V | R EQ 2 = 160 k 43 k = 33.9 k I C 2 = 150 3.18- 0.7 33.9 k +151 1.6 k ( 29 =1.35 mA | V CE 2 = 15 - 4.7 k Ω+ 151 150 1.6 k I C = 6.49 V g m 2 = 40 1.35 mA ( 29 = 54.0 mS | r p 2 = 150 54.0 mS = 2.78 k | r o 2 = 80 + 6.49 ( 29 V 1.35 mA = 64.1 k Q 3 : V EQ 3 = 15 120 k 120 k Ω+ 91 k = 8.53 V | R EQ 3 = 120 k 91 k = 51.8 k I C 3 = 80 8.53- 0.7 51.8 k +81 2.2 k ( 29 = 2.72 mA | V CE 3 = 15 - 81 80 2.2 k I C = 8.93 V g m 3 = 40 2.72 mA ( 29 = 109 mS | r o 3 = 60 + 8.93 ( 29 V 2.72 mA = 25.3 k | r p 3 = 80 109 mS = 734 A v = R G 10 k Ω+ R G A vt 1 A vt 2 A vt 3 A vt 1 =- 2 mS ( 29 301 k 15 k 33.9 k 2.78 k ( 29 =- 4.36 A vt 2 =- 54.0 mS ( 29 64.1 k 4.7 k 51.8 k 734
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HW10_Solutions - Homework Solutions HW 10 14.102 M1 : ID =...

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