HW sol 1.pdf - Homework solution to Advanced Thermodynamics#1 1.3-2 10.0129X 11.0093(1-X = 10.811 X = 0.199 1.3-4 Let N be initial mole number of the

HW sol 1.pdf - Homework solution to Advanced...

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Homework solution to Advanced Thermodynamics #1 1.3-2 10.0129X + 11.0093(1-X) = 10.811 X = 0.199 1.3-4 Let N be initial mole number of the sample Total mass 0.01 kg = (1 + 0.9 + 0.8)N 3 10 kg N = 3.7 mole Let ' N be the number of moles of 2 D to be added, 0.2 ' ' N N N N = 0.3 so ' N = 0.53 moles So mass of 2 D = 0.53 4 3 10 = 2.1 3 10 kg 1.3-5 Let X be the mole fraction and N be the mole number 342 342 18(1 ) XN XN X N = 0.2 So X =1.3 % 1.3-6 Let s M be the molecular mass (weight) Let N be the total mole number 3 (0.1 ) (0.9 )18 10 0.1029 s N M N 0.1 0.07 0.036/ 0.018 N N So N = 4.67, s M = 0.0584 kg Hence NaCl is a plausible guess
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