ARC322 Homework 9 Module 13 SOLUTION 2008

# ARC322 Homework 9 Module 13 SOLUTION 2008 - ARC322...

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ARC322 Homework #9 … Module 13 15 Points KEY 1. A cantilever beam has an L of 8 ft and supports a load of 1875 lb/ft 6 ft from the root of the beam to the 6 ft location. Select a WF member based on a calculated S. 3 points M = w L 2 /2 = (1875 lb/ft)(6 ft) 2 /2 = 33,750 ft-lb S = M/ f = (33,750 ft-lb x 12 in/ft)/24,000 lb/in 2 = 16.875 in 3 W12x16 S = 17.1 in 3 > 16.875 in 3 … OK If we add the weight of the WF will S still be OK? 2. A cantilever beam has an L of 5 ft and has a point load of 4200 lb at its end. Select a WF member based on a calculated S. 2 points M = PL = 4200 lb x 5 ft = 21,000 ft-lb S = M/ f = (21,000 ft-lb x 12 in/ft)/24,000 lb/in 2 = 10.5 in 3 W10x12 S = 10.9 in 3 > 10.5 in 3 … OK … will it work when the weight of the beam is added? 3. A simple beam spans 42 ft and carries a concentrated load of 18,000 lb that is 12 ft from its left reaction. Select a WF member based on a calculated S. 2 points M = Pab /L = (18,000 lb X 30 ft x 12 ft )/42 ft = 154,286 ft-lb S = M/ f = ( 154,286 ft-lb x 12 in/ft)/24,000 lb/in 2 = 77.14 in 3 W21x44 S = 81.6 in 3 > 77.14 in 3 … OK … will it work when the weight of the beam is added?

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