Unformatted text preview: length. What is its maximum moment? No sketch required. M = w L 2 /2 = (550 lb/ft x (13 ft) 2 )/2 = 4. A simple steel beam spans 32 ft. It carries a point load of 5,500 lb 10 ft from R 1 . What are R 1 and R 2 ? No Sketch required. R 1 = Pb/L = (5500 lb x (32 ft – 10 ft))/32 ft = R 2 = Pa/L = (5500 lb x (32 ft – 20 ft))/32 ft = 5. What is the maximum moment for the beam in Question 4? No Sketch required. M = Pab/L = (5500 lb x 10 ft x 22 ft)/32 ft = Required S = 48.24 in 3 Required S = 5.25 in 3 46,475 ftlb R 2 = 1,718.75 lb M = 37,812.5 lb R 1 = 3,781.25 lb...
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This note was uploaded on 03/30/2008 for the course ARC 322 taught by Professor Mcgavin during the Winter '08 term at Cal Poly Pomona.
 Winter '08
 McGavin

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