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Unformatted text preview: F = P/A = 130,000 lb/ ((3.14 x (4 in) 2 (3.14 x (3.5 in) 2 ) F = 11,036 lb/in 2 (rounded) 3 Has the actual stress exceeded the allowable stress? 11,036 lb/in 2 < 24,000 lb/in 2 OK 4 What would the maximum unsupported length of the column need to be in order to use the next smaller diameter pipe? 14 ft 5 What is the total weight of the column in question 1? 15 ft x 43.39 lb/ft = 650.85 lb say 651 lb...
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This note was uploaded on 03/30/2008 for the course ARC 322 taught by Professor Mcgavin during the Winter '08 term at Cal Poly Pomona.
 Winter '08
 McGavin

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