chap01

chap01 - Chapter 1 Solution 1(a q = 6.482x1017...

Info icon This preview shows pages 1–4. Sign up to view the full content.

View Full Document Right Arrow Icon
Chapter 1, Solution 1 (a) q = 6.482x10 17 x [-1.602x10 -19 C] = -0.10384 C (b) q = 1 . 24x10 18 x [-1.602x10 -19 C] = -0.19865 C (c) q = 2.46x10 19 x [-1.602x10 -19 C] = -3.941 C (d) q = 1.628x10 20 x [-1.602x10 -19 C] = -26.08 C Chapter 1, Solution 2 (a) i = dq/dt = 3 mA (b) i = dq/dt = (16t + 4) A (c) i = dq/dt = (-3e -t + 10e -2t ) nA (d) i=dq/dt = 1200 120 π π cos t pA (e) i =dq/dt = + e t t 4 80 50 1000 50 ( cos sin ) A µ t Chapter 1, Solution 3 (a) C 1) (3t + = + = q(0) i(t)dt q(t) (b) mC 5t) (t 2 + = + + = q(v) dt s) (2t q(t) (c) ( ) q(t) 20 cos 10t / 6 q(0) (2sin(10 / 6) 1) C t π π µ = + + = + + (d) C 40t) sin 0.12 t (0.16cos40 e 30t - + = + = + = t) cos 40 - t 40 sin 30 ( 1600 900 e 10 q(0) t 40 sin 10e q(t) -30t 30t - Chapter 1, Solution 4 ( ) mC 4.698 = = = = = π π π 06 . 0 cos 1 6 5 t π 6 cos 6 5 dt t π 6 5sin idt q 10 0
Image of page 1

Info icon This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document Right Arrow Icon
Chapter 1, Solution 5 μC mC ) e 1 ( 2 1 e 2 1 - mC dt e idt q 4 2 0 2t - 2t - 490 = = = = = Chapter 1, Solution 6 (a) At t = 1ms, mA 40 = = = 2 80 dt dq i (b) At t = 6ms, mA 0 = = dt dq i (c) At t = 10ms, mA 20 - = = = 4 80 dt dq i Chapter 1, Solution 7 < < < < < < = = 8 t 6 25A, 6 t 2 25A, - 2 t 0 A, 25 dt dq i which is sketched below:
Image of page 2
Chapter 1, Solution 8 C 15 μ 1 10 2 1 10 idt q = × + × = = Chapter 1, Solution 9 (a) C 10 = = = 1 0 dt 10 idt q (b) C 22.5 = + = × + × + × = = 25 10 15 1 5 2 1 5 10 1 10 idt q 3 0 (c) C 30 = + + = = 10 10 10 idt 5 0 q Chapter 1, Solution 10 q ixt x x x = = = 8 10 15 10 120 3 6 C µ Chapter 1, Solution 11 q = it = 85 x10 -3 x 12 x 60 x 60 = 3,672 C E = pt = ivt = qv = 3672 x1.2 = 4406.4 J Chapter 1, Solution 12
Image of page 3

Info icon This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document Right Arrow Icon
Image of page 4
This is the end of the preview. Sign up to access the rest of the document.

{[ snackBarMessage ]}

What students are saying

  • Left Quote Icon

    As a current student on this bumpy collegiate pathway, I stumbled upon Course Hero, where I can find study resources for nearly all my courses, get online help from tutors 24/7, and even share my old projects, papers, and lecture notes with other students.

    Student Picture

    Kiran Temple University Fox School of Business ‘17, Course Hero Intern

  • Left Quote Icon

    I cannot even describe how much Course Hero helped me this summer. It’s truly become something I can always rely on and help me. In the end, I was not only able to survive summer classes, but I was able to thrive thanks to Course Hero.

    Student Picture

    Dana University of Pennsylvania ‘17, Course Hero Intern

  • Left Quote Icon

    The ability to access any university’s resources through Course Hero proved invaluable in my case. I was behind on Tulane coursework and actually used UCLA’s materials to help me move forward and get everything together on time.

    Student Picture

    Jill Tulane University ‘16, Course Hero Intern