chap01

chap01 - Chapter 1 Solution 1(a q = 6.482x10 17...

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Unformatted text preview: Chapter 1, Solution 1 (a) q = 6.482x10 17 x [-1.602x10-19 C] = -0.10384 C (b) q = 1 . 24x10 18 x [-1.602x10-19 C] = -0.19865 C (c) q = 2.46x10 19 x [-1.602x10-19 C] = -3.941 C (d) q = 1.628x10 20 x [-1.602x10-19 C] = -26.08 C Chapter 1, Solution 2 (a) i = dq/dt = 3 mA (b) i = dq/dt = (16t + 4) A (c) i = dq/dt = (-3e-t + 10e-2t ) nA (d) i=dq/dt = 1200 120 π π cos t pA (e) i =dq/dt = − + − e t t 4 80 50 1000 50 ( cos sin ) A µ t Chapter 1, Solution 3 (a) C 1) (3t + = + = ∫ q(0) i(t)dt q(t) (b) mC 5t) (t 2 + = + + = ∫ q(v) dt s) (2t q(t) (c) ( ) q(t) 20 cos 10t / 6 q(0) (2sin(10 / 6) 1) C t π π µ = + + = + + ∫ (d) C 40t) sin 0.12 t (0.16cos40 e 30t- + − = − + = + = ∫ t) cos 40- t 40 sin 30 ( 1600 900 e 10 q(0) t 40 sin 10e q(t)-30t 30t- Chapter 1, Solution 4 ( ) mC 4.698 = − = − = = = ∫ ∫ π π π 06 . cos 1 6 5 t π 6 cos 6 5 dt t π 6 5sin idt q 10 Chapter 1, Solution 5 μC mC ) e 1 ( 2 1 e 2 1- mC dt e idt q 4 2 2t- 2t- 490 = − = = = = ∫ ∫ Chapter 1, Solution 6 (a) At t = 1ms, mA 40 = = = 2 80 dt dq i (b) At t = 6ms, mA = = dt dq i (c) At t = 10ms, mA 20- = = = 4 80 dt dq i Chapter 1, Solution 7      < < < < < < = = 8 t 6 25A, 6 t 2 25A,- 2 t A, 25 dt dq i which is sketched below: Chapter 1, Solution 8 C 15 μ 1 10 2 1 10 idt q = × + × = = ∫ Chapter 1, Solution 9 (a) C 10 = = = ∫ ∫ 1 dt 10 idt q (b) C 22.5 = − + = × +       × − + × = = ∫ 25 10 15 1 5 2 1 5 10 1 10 idt q 3 (c) C 30 = + + = = ∫ 10 10 10 idt 5 q Chapter 1, Solution 10 q ixt x x x...
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This document was uploaded on 01/24/2008.

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chap01 - Chapter 1 Solution 1(a q = 6.482x10 17...

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