Homework_1_Solutions

Homework_1_Solutions - f 2 o {C 8 Homewark iii 80 Whom. 1,...

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Unformatted text preview: f 2 o {C 8 Homewark iii 80 Whom. 1, fizvflu’gé ,§:5§+2g-6§ m UM} : 10+53fi+(0+133+(3—e)§|=15§+2§'3%\=5(e\1+(z¥‘+(—3§1 = SK‘g = 5(“333 ' (5§+Zg~é%: (5§+15§§_(5;+zg,9§3 : (HM +(o-2\g+ (mag: m -2g+2\2 = C.) The Componznjc 6F A (3‘0an (5 = 0 d3 3mg : 3mg) +6243 433: (3+5)i+(o+1\g+(Q-Q%: <3§+2g+5£ an»: , WW _ - 13M} " I‘zimgé-fl— W _ KLan Mfiar meQeQ £0 3K4? : i ‘ 5524- 23 + 31:? : 31+ 253 +5”: : --»§~»w~~ D3" ms :3 2. Al‘f‘pme ground gem: ESOEm/hr W 3 E: '350§< Wind 3pm r 40mm NW : c3:40ml35°€<+4os§n135°grummum True, cur Swen? ' ’9 '- gift» we, mm : m s = 3mm bum/hr diredfion: 9: Jan"(%= Jam“ gm: 4.736;" +\%o° -: l?5.724° WWWMWE o (buma H‘s {\n Qumdran* true mgwa and} (imam. Eamon/m @ 4.1%? mm sew: a: *ng a, : (—3503?) +(-2&2<a4<2 + amt; g‘) = 3%. 1‘54? + 28.2645“; A. '5. K: €032 ant? TE: 5§+2g — 6'2 «3 RM GAE = Axgx “’ k333+A232 : WMCMQAQ .-. om +(o\(2“;+(s\<vé\ = (m>(m) mam - 6 + O _ * )0\)(\; GS- ) 60$(eAE\ é ‘f ‘ A $— w .. e Jlo‘ms S a?) ’ . A 1‘ G =: _ l “WWW 0510 and APA > 9A8: COS um.st ammo; (3&8: mama} . 3’ _, (I)(s)+(c>\(2‘3+€3‘:(-63 —: 43 " J b3 Pamflflafi Wheat Fri: 3—3 : g : WE : 45.2003 : Bl (5631+(2V‘H-6Y‘ )2 65 {Sam as 553+1Q'63) V‘\\ m . . NH..M~¢WT_, '0-200{S,1,-e> =S\-£§_:o.4g+l.2% =v‘fi F eremi‘m‘w- Cmnponen‘iz: R: A r‘v’x : 0,0, 3) - <-1,-o.4,l.2> = <2,o.4,1.z> E: ELLE? (New Subtracténfl {5m pmiiéfi " Compnw": mm Huvuiarvm mi}: M flu; perpendh‘emr Eon:me flnmnw-m .4. Mn. . . Q J A * i {Z A i A A C=Kx5= : 4H ‘2, :35:+243—K;i -6 -4- .c, 44 +-|6x — 2g “£2 4 \* -15Q+21g+\o£ : c J ‘6 ILIQHQ littfiwi 5,, 53, +537 A : w : : : .——o« ‘ -—~ ME Du \imwmuml F5” 3 X 3 3 3 §Ca€ar (Somme/143 O; 6 (n We direction (7? TS: Du (‘3 ‘3“ = {43361;}+(123(%?;+m(.§3 : 44.433 k‘-u,_,..._..‘_.. , w- Vecbr Components: (0-5071 ‘—‘- C25§\<% ' 5.i:2§2~2g+2§, §:\a—--2g+sa vector perpendicu‘txr 43:; 100% 23 ME : U: 6=Kx*é: 9% 3:3 ' ‘e§+2g—4£ 3 ‘ ‘+ ufi’aa +12% '1 aw"; C = ~12 4:55 —- 2.2 unit vujoor WWWMM $0 EWA 7i amzflé ? ax it" ‘9'“: M, <‘2."4/'1> ’_’(-2,-4,—2) ’ U (’2§1*(_q\1+(’2)1 I _ __ Mwwwm “M W wwwmm m? (4/‘21‘45 LEW/ids? Av J5 _ ‘1 3 w m e. v(f3=v(x,%,2\= 32+(Qx)3-3603C3) VoPcs, POM} , (Mama) WP) =\/(M,13= e,’ + (20333 —'s‘cosm :: 4-0“? Ms W®= \I(OIOIO\ 2 Co “ (2&9? 'BGOSQQ = -Z.0()0 VoH‘s Vommrz Wech : \rmvvm = (4m; MA— (-2.000 Mg) 7- VOHPS : EJ698123: (x—Z\Q+CX+2)g V/ln I 136$ij (EA, Q(X1,82,21\3 4:07): E6“ I g\ I 2') : (X|“2I))Q+(XI+ 2:33 V/m m = «3 01.3121» .-. (ma 32+ (x2 +£7.35; WM 1-? {he dedn‘c 942095 on; [Owémdt’culm £11m, ECP‘B'ECmmO é £09» 23(53):- + ambecaxg = o (X. —Z.\(xz -z,) 4» (m+2.)(x1+ 223: 0 “m2 M1 :Xflfizyzifi (ylxiwa‘z’txflhzzfi =0 1 Zylxl+22I22=zO $ ZXDXZ: _22121 :7 ¥|¥2:‘2g21 Am; two poi‘njcs ?and G) ‘UMJC safs‘sfl/ 8m amt-(on ‘Xfléz I “Z: 21 Com be. usufl m) win We Jaw elm‘n‘c ‘20le mL P be perpendraufan 190 “Elm metric M 4+ 62. One, possibflffy 1% WAN) and @(|,|,“\ (Pkiflmxr- (MW +o+ x33 Wm: o§+2g V/m Z 2(a):Emu-w:(1+n+u—\\3v1m= Z§+Ong ...
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Homework_1_Solutions - f 2 o {C 8 Homewark iii 80 Whom. 1,...

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