EXPT08 - Experiment 8: Mesh Currents and Node Voltage...

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Experiment 8: Mesh Currents and Node Voltage Analysis Procedure: 1. Using both the node voltage analysis method and the mesh current analysis, I ended up with systems of equations that I simply used Matlab to solve. I got identical results when I used both methods, I got that iL = -3.23mA and VL = -2.20V. 2. 3. 4. Unfortunately, I do not have a digital camera to take a picture of my circuit, but I am saving it for use in lab 9 anyway, so I am not disassembling it. 5. Measured values: iL = -3.19mA, and VL = -2.16V 6. % deviation for iL = -.04 / -3.23 * 100 = 1.23%, % deviation for VL = -.04/-2.20 * 100 = 1.82% 7. My calculated results from step 1 were very similar to the lab results, but not exactly equal. There was a very small percent deviation for both, but there was some deviation nonetheless. The differences can most likely be attributed to one of a couple things. I had to truncate my decimals when I was doing my math, and the loss of some significant digits could be the reason for the slight
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EXPT08 - Experiment 8: Mesh Currents and Node Voltage...

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