EXPT09 - Experiment 9: Mesh Current and Node Voltage...

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Experiment 9: Mesh Current and Node Voltage Analysis Procedure: 1. a. VL = -2.16V, iL = -7.09mA, P = -.11mW b. VL = 1.90V, iL = 6.22mA, P = .074 mW c. VL = -4.06V, iL = -13.32mA, P = -.72mW 2. -2.16 = 1.06 + -3.22, -7.09 = 3.42 + -10.51 3. I cannot draw the circuit because I do not have a tablet pc. Vth = 2.09V, Rth = .295 k Ohms 4. 5.
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6. 7. 8. I cannot take a picture of my circuit because I don’t have a digital camera.
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9. VL = -2.16V, iL = -7.09mA, 0% deviation 10. VL = 1.90V, iL = 6.22mA, 0% deviation 11. VL = -4.06V, iL = -13.32mA, 0% deviation 12. VL1 = 1.90 + -4.06 = -2.16 13. My results are identical to the results I obtained initially through calculations. This confirms the superposition theory. 14. iL1 = 6.22 + -13.32 = -7.09. 0% deviation. This once again confirms the superposition theory. 15. PL1 = .074 + -.72 = -.646mW 16. N/A 17. Vth = 2.09V 18. N/A 19. .295k Ohms = Rth 20. N/A 21. ioc = -7.09mA, 2.09/-7.09 = .295k 22. There is no percent deviation, for my results were identical, thus proving the
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This lab report was uploaded on 03/30/2008 for the course ECE 2074 taught by Professor Stilwell during the Spring '08 term at Virginia Tech.

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EXPT09 - Experiment 9: Mesh Current and Node Voltage...

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