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Unformatted text preview: 1cos x ≤  x  and the Sanwich Theorem to show that lim x → cos x = 1. Hint: What is lim x → (1cos x )? 3 c) For any function f ( x ), if lim x → c  f ( x )  = 0, then lim x → f ( x ) = 0. THEOREM 5 If for all x in some open interval containing c , except possibly at x = c itself, and the limits of f and g both exist as x approaches c , then Example 12 If lim x →2 f ( x ) x 2 = 1, ﬁnd a) lim x →2 f ( x ) 4 b) lim x →2 f ( x ) x Example 14 lim x → sin 2 x lim x → √ 1 + cos 2 x 5...
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 Spring '08
 FBHinkelmann
 Calculus, Factoring, Squeeze Theorem, Limit, Limit of a function, open interval containing, Sandwish Theorem

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