SNHU
MAT 136 Discussion 2-1 Linear Equations
Of the three ways to solve a system of equations I found that utilizing the
elimination process was the most efficient for me. This process allows the student
to line up each equation on top of one another and find the X or Y value by
addition or subtraction.
X + Y = 6
X - Y= 2
2X = 8
2
X/2
= 8/2
X = 4
X=4
Now all you must do to complete the equation is plug the X (4) in either equation
(X + Y = 6 or X - Y = 2) to solve for (Y).
4 + Y = 6
-4 = -4
Y = 2
Leaving you with
(4,2) for your final answer.
While trying to use the substitution method, I found that the overall equation was
more complex than it needed to be in my humble opinion. Solving by graphing
was graphing was great if you needed a visual representation on how to complete
the equation.