MATH test 2 KEY

MATH test 2 KEY - f ( t ) = t 2 ! 5 t + 6 on [ ! 1,5] 1 6 t...

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Math 2015 Test 2 Spring 2007 Answers 1. Evaluate cos x sin 3 x dx ! . u = sin x ; du = cos xdx ans : 1 4 sin 4 x + C 2. Find x 1 + x 2 dx 1 2 ! . u = 1 + x 2 ; du = 2 xdx ; when x = 1, u = 2; when x = 2, u = 5 1 2 1 u du 2 5 ! = 1 2 ln u 2 5 = 1 2 ln 5 2 " # $ % 3. Solve ! F ( x ) = 3 x 2 + 1 x with F (1) = 5 . F ( x ) = x 3 + ln x + 4 4. ! T = k ( T " 60) C = 20; k = ln(0.75) 2 # " 0.144 T = 60 + 20 e " 0.144 t t = " 4.6 hours; 4.6 hours before midnight 5. Smallest: (5, ! 6) Largest: (0, 1) 6. Evaluate 3 e ! 2 x dx 0 " # = 3 2 . 7. Determine the average value of the following function in the given interval.
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Unformatted text preview: f ( t ) = t 2 ! 5 t + 6 on [ ! 1,5] 1 6 t 2 ! 5 t + 6 ! 1 5 " dt = 3 8. Find x 2 x 3 + 1 dx ! u = x 3 + 1 ! du = 3 x 2 dx ; ans : 2 9 x 3 + 1 ( ) 3 2 + C MULTIPLE CHOICE: Answers: 4, 3, 1, 2, 4, 2, 4, 1, 3, 2, 3, 4, 1, 2, 3...
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This note was uploaded on 03/31/2008 for the course MATH 2015 taught by Professor Awkohler during the Spring '06 term at Virginia Tech.

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