{[ promptMessage ]}

Bookmark it

{[ promptMessage ]}

Chapter 11 Notes

# Chapter 11 Notes - -Chapter 11Chapter 11 Reaction in...

This preview shows pages 1–2. Sign up to view the full content.

-Chapter 11- 1 Chapter 11: Reaction in Aqueous Solutions II: Calculations [11-1] Calculations involving Molarity Review! o Molarity= molar concentration= M= [x] = moles solute/ L of soln o Reaction ratio/ molar ratio The relative number of moles of reactants and products shown in the balanced chemical equation Use coefficients in front of the chemical species Also called stoichiometry Mole ratios can also be obtained from the chemical formula for a substance o EX: what is the molar concentration H3O+ in .250 M soln of H2SO4? This is a diprotic (i.e. 2step.. goes from H2SO4 to HSO4(-) to SO4(2-)) and it goes from a 1:2 molar ratio… so .250M x 2 = 0.500M of H3O+ o EX: what volume of .5M H2SO4 is required to completely react with 100mL of 1M NaOH H2SO4 + 2NaOH -> Na2SO4 +2H2O…. see notebook for explanation; end result is 100mL….. find mols of NaOH, molar ratio, then molarity o Ex: 100mL of 1M NaOH and 100mL of 1M H2SO4 mixed. Determine all concentrations See notebook for work…. determine limiting reagent (no limiting reagent in this rxn); determine amount of product formed (use molar ratio); then use initial/change/end (ICE) chart.. and use molar ratio to add and subtract from

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
This is the end of the preview. Sign up to access the rest of the document.

{[ snackBarMessage ]}