Basic Engineering Circuit Analysis-7th Ed-J. David Irwin

Basic Engineering Circuit Analysis

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Answers to Selected Problems 1 Chapter 1 1.1 i=2 A 1.4 Q=1.5 C 1.7 (a) P =–18 W (supplied) (b) P =–18 W (supplied) 1.10 (a) P =–12 W (supplied) (b) P =24 W (absorbed) 1.13 P 2 =48 W (absorbed) 1.17 P 36V =–144 W, P 1 =48 W, P 2 =48 W, P DS =–8 W, P 3 =56 W 1.20 V x =18 V Chapter 2 2.1 I=0.3 mA, P=1.8 mW 2.4 R x =5 k 2.7 P S =72 W 2.10 I 1 =6 mA, I 2 =3 mA 2.12 I x =–8 mA, I y =±10 mA, I z =–2 mA 2.14 I x =9 mA, I y =–10 mA, I z =–2 mA 2.17 V x =3 V 2.19 V ad =7 V 2.22 V ad =9 V, V ce =11 V 2.25 V x =10 V 2.27 V x =5 V 2.29 P 30k =1.2 mW 2.31 =90 mA 2.34 =4 mA 2.36 I L =0.4 mA 2.39 R AB =3 k 2.41 R AB =2 k 2.44 (a) Min =950 , Max =1050 (b) Min =460.6 , Max =479.4 (c) Min =19.8 k , Max =24.2 k 2.47 (a) R Nom =3 (b) Positive/Negative Tolerances = ; 8.33 % 2.50 I 1 =3 mA 2.52 2.55 2.58 V S =12 V 2.60 V S =48 V 2.63 V S =38 V 2.65 V S =30 V 2.68 I S =4.5 A 2.70 =6 mA 2.72 P=63 mW 2.75 =4 A 2.78 =10 V 2.80 =2 V 2.83 =–20 mA 2.86 Power gain =1.422 2.87 P 10k =10 mW 2FE-1 P =1.2 W 2FE-4 I o = - 4 9 mA kW W I o V o V o I o I o I o = 2 mA V o = - 16 3 V I o I o IRW-ANSW.I 3-05-2001 12:37 Page 1
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2 A N S W E R S T O S E L E C T E D P R O B L E M S Chapter 3 3.1 =1 mA 3.3 V 2 =22 V 3.5 =0.6 mA 3.8 =1.25 mA 3.10 =2 mA, I 1 =–6 mA 3.13 =–1 mA 3.15 3.18 =–1.5 mA 3.21 =2 V 3.24 =–4.8 mA 3.27 =4.36 V 3.30 =1.5 mA 3.33 3.36 =–0.4 mA 3.39 =32.25 V 3.42 =4 V 3.44 3.47 =7 mA 3.50 =5.2 mA 3.53 =0.4 mA 3.56 =6 V 3.59 3.62 =3 V 3.65 =6 V 3.68 3.70 =–5 V 3.73 3FE-1 3FE-4 =–3.27 V 3FE-6 =6 V V o V o V o = 10 3 V V o i S = - 1 V o V o = - 7 8 V V o V o V o = 8 5 V V o I o I o I o V o = 4 3 V V o V o I o V o = 4 3 V I o V o I o V o I o V o = - 5 6 V I o I o I o I o I o Chapter 4 4.1 4.3 =0.75 V 4.5 4.8 =–4.25 V 4.10 =2.4 mA 4.12 =0.5 mA 4.15 =0.4 mA 4.18 =10.5 V 4.21 =2 V 4.24 4.27 =–1 mA 4.29 =–0.2 mA 4.31 =0.67 mA 4.33 =4.8 V 4.36 =8 V 4.39 4.42 =2 mA 4.44 =1.25 mA 4.47 =1.55 V 4.50 R AB =1 k 4.52 =–6 V 4.55 =5.71 mA 4.58 =0.43 V 4.61 =2.18 V 4.64 =1.2 mA 4.67 =258 mV 4.70 R L =2 k , 4.72 R L =6 k , 4.75 =2 V 4FE-1 P L =8 mW 4FE-3 R L =12.92 V o P L = 25 6 mW P L = 12.5 mW V o I o V o V o I o V o V o I o I o V o = 8 5 V V o V o I o I o I o I o = - 7 5 mA V o V o I o I o I o V o I o = - 16 5 mA V o I o = 8 7 mA IRW-ANSW.I 3-05-2001 12:37 Page 2
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Chapter 5 5.1 v(t=4)=40 V 5.3 C=120 F 5.5 i(t)= ; 2.92 cos 377 t A 5.7 (a) i(t)=4.52 cos 377 t A (b) w(t)=360 sin (754t-90 ° ) mJ 5.9 v(t)=100t V 0 t 2 ms =0.2 V t>2 ms 5.11 i(t)=6 mA 0 t 2 ms =–6 mA 2 t 4 ms 5.14 i(t)=0.6 A 0 t 2 s =–2.4 A 2 t 3 s =0.6 A 3 t 5 s =0 t>5 s 5.16 i(t)=24 A 0 t 6 s =–60 A 6 t 10 s =16 A 10 t 16 s =0 t>16 s 5.19 i(t)=377 cos (2000 t) mA 5.21 (a) v(t)=75.4 cos 377t V (b) w(t)=0.1-0.1 cos 754t J 5.24 (a) v(t)=0 , t<0 =250e –t V, t>0 (b) w(t)=1.25 C 1-2e –t +e –2t D J 5.27 v(t=5 s )=–0.91 V w(t=5 s )=91.97 J t ( s ) –400 0 400 0.2 0.4 0.6 0.8 0 i(t) ( mA ) 1 t ( s ) –70 –50 –30 –10 10 30 2 4 6 8 10 12 14 16 0 i(t) ( A ) 18 A N S W E R S T O S E L E C T E D P R O B L E M S 3 IRW-ANSW.I 3-05-2001 12:37 Page 3
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5.29 v(t)=0 0 t 2 ms =–2.5 V 2 t 4 ms =2.5 V 4 t 8 ms =–2.5 8 t 10 ms =0 t>10 ms 5.31 v(t)=6.67 mV 0 t 3 s =–10 mV 3 t 6 s =0 6 t 9 s =25 mV 9 t 11 s =0 t>11 s 5.33 i(t)=0.5t A 0 t 2 ms =3*10 –3 -t A 2 t 3 ms =0 t 7 3 ms 5.36 t ( ms ) –60 60 40 20 0 –20 –40 –6 3 2 0 –2 –3 –5 1 2 3 4 5 6 7 0 i c (t) ( mA ) i(t) ( mA ) 8 v(t) i(t) @ C MIN i(t) @ C MAX t ( s ) –15 30 15 0 3 0 v(t) ( mV ) 6 9 12 t ( ms ) –3 –2 –1 1 2 0 3 2 0 v(t) ( V ) 4 6 8 10 12 4 A N S W E R S T O S E L E C T E D P R O B L E M S IRW-ANSW.I 3-05-2001 12:37 Page 4
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5.38 5.41 C 1 =1 F, C 2 =3 F, and C 3 =4 F 5.44 =12 V 5.46 C=3 F 5.49 C T =2 F 5.51 C T =9 F 5.54 (a) C NOM =1.43 F (b) C MIN =1.254 F, C MAX =1.606 F (c) % MIN =–12.3% , % MAX =12.3% 5.56 L=20 mH 5.59 L AB =5 mH 5.61 L AB =6 mH 5.64 C=1.25 F 5FE-1 Chapter 6 6.1 v C (t)=12-8e –t/0.6 V, t>0 6.3 v C (t)=6e –t/0.4 V, t>0 6.5 t>0 i o ( t ) = 2 3 e - 10t A , 2 F 4 F 6 F V o C 1 C 2 C 3 t ( ms ) –1.5 –1 –0.5 0 0.5 1 1.5 –0.8 0.4 0.2 0 –0.2 –0.4 –0.6 0 1 2 3 4 5 i(t) (
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