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**Unformatted text preview: **“Omewode _ ‘Fkymots’ PROBLEM 2.C1 Using computational software, determine
the magnitude and direction of the
resultant of n coplanar forces applied at
pointA. Wm.
WP Qe cud?- ﬁat/«Same?» ikm‘k‘
may}: C30 “1% my @«wﬁram
await! R
@3713 ‘i‘ecuq "‘E’
Rx
lnpu'i' ‘3, 1H: Forces) *anoGlea POr‘ s|>©L"'&“
F, ) F; .... F5 ? KDo wmpuier‘ at“... ééﬁvﬁﬂa$ er mamas: Mos-K» on; vaccimw; ) So *1", gamer—L 4-0 rodeoms, 'i’é (LG w“; r‘L‘ EDKLl< __ 12st)
92 _GR & W /_.__, ¥\ow«€vaor”Ka ~Fau?:, Zyﬁéf4
Q.CL\ Q0r\¥
n=3
theta = [22.6 118.1 349.6] 711‘; ‘ﬁ ”5"“
thetal = theta +“:‘&“%‘“ Qﬁﬁ"ﬂ
force = [390 680 610] A yrobtem 22—3
= *0 ‘
theta theta* pi/l80 Convcﬁo’f‘knﬁ QA¢ 1.39]
sumx = O
sumy = O o for i=lzn
sumx = sumx + force(i)*cos(theta(i))
sumy = sumy + force(i 1)*sin(theta(i)) R = sqrt(sumxA2+sumyA2) thetar = atan(sumy/sumx) thetar = thetar*180/pi canvevr'k‘a‘xﬂ if thetar<0 “ﬁg“
thetar = thetar + 360; end $ee. Wing“ 16.53:“; Cw W‘ﬁw‘r M MATLME @Mmamé w 9/10/07 11:46 AM MATLAB Command Window theta = 22.6000 118.1000 349.6000 thetal = 22.6000 118.1000 349.6000 force 390 680 610 theta 1| 0.3944 2.0612 6.1017 sumx = sumy = sumx = 360.0520 sumy = 149.8752 sumx = 9/10/07 11:46 AM MATLAB Command Window 2 of 2 —_____—__—_—_——_——-———————————————-————-——
__—___________..—._______————————-——-——-_————— 39.7639 sumy = 749.7214 sumx = 639.7425 sumy = 639.6048 904.6351 thetar = 0.7853 thetar =
44.9938 >> ...

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- Fall '07
- MaureenA.McGraw
- mechanics