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Exam 1 S Green Ve 1a) Boxplo 1a) The m 1c) Left F 2a) P(X≥7 2b) ˆ ( P p > 3) a) 149 c) 1.00 4a) i) 15 4b) Yes, 4c) No, N 5a&b) ( / .8 / (T+) .080 5c) 80/12 6a) P(X<4 6b) 4.9 – 6c) ( 5) P X < (uses Cen Summer 201 ersion ot mean is greate Fence = 69-(1. ) = 0.514 (ad 0.68) P = 9 ± (2)21 = 10 0 d) -0.76 0/500 = 0.30 Independent Not Independe / \ .10/ (D+) / \ \ .2 .0 (T-) (T .020 .0 5= 0.64 4) = P(<Z<-1.2 0.67(0.7) = 4 5 ) 0 P Z = > tral Limit The 19 er than the m .5)(10) = 54 dd up binomia 0.68 0 0.02 Z > 07 to 191 gram e) Apple is m ii) P(T ent P(C \ .90 (D-) / \ 5/ \ .95 T+) (T-) 045 .855 29) = 0.0985 4.43 minutes 4.9 .7 30 P = eorem) median (skewe Yes, 13 is a al values from ( 0.65 1 P Z = ms b) 120 ± more unusual, 30/500 = 0.06 Tea) = 0.30 Coffee) = 0.40 ( ) 0.78 P Z < ed positive) a possible out m 7 to 10) ) 1.43 1 Z > = ± (1)13 = gram , z-score furth 6 iii) 1 P(Te 0 P(Co 0.7823 = Diabet No Dia Total tlier .9236 0.0 = ms107 to 133 her from zero 15/100 = 0.15 ea|Stan) =0.30 offee|USF) = Tes tes 80 abetes 20 100 0764 o 5 0 they a 0.30 they a st+ Test- 45 855 0 900 are equal are not equal Total 125 875 1000

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