Ch 16 hw 1

# Ch 16 hw 1 - 1. 1/1 points | 1/4 submissions Last Response...

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1. 1/1 points | 1/4 submissions Last Response | Show Details All Responses Notes What is the kinetic energy of a proton that is traveling at a speed of 2400 m/s? K = 4.8096e-21 [4.90e-21] J 2. 1/1 points | 1/4 submissions Last Response | Show Details All Responses Notes If the kinetic energy of an electron is 5.2e-18 J, what is the speed of the electron? (You can use the approximate (nonrelativistic) formula here.) v = 3399346.342 [3.40e+06] m/s 3. 5.5/5.5 points | 3/4 submissions Last Response | Show Details All Responses Notes Locations A , B , and C are in a region of uniform electric field, as shown in the diagram above. Location A is at < -0.5 , 0, 0>m. Location B is at < 0.4 , 0, 0>m. In the region the electric field = < 850 , 0, 0> N/C. For a path starting at B and ending at A , calculate: (a) The displacement vector = < -0.9 [-0.9] , 0 [0] , 0 [0] > m (a) the change in electric potential: V = 765 [765] volts (b) the potential energy change for the system when a proton moves from

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## This note was uploaded on 03/31/2008 for the course PY 208M taught by Professor Chabay during the Spring '08 term at N.C. State.

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Ch 16 hw 1 - 1. 1/1 points | 1/4 submissions Last Response...

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