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Ch 20 hw 2

# Ch 20 hw 2 - 1[MI02 20.P.00a 9/9 points | 4/4 submissions...

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1. [MI02 20.P.00a.] 9/9 points | 4/4 submissions Last Response | Show Details A long straight wire suspended in the air carries a conventional current of 8.5 amperes in the -x direction as shown (the wire runs along the x-axis). At a particular instant an electron at location < 0, -0.003 , 0> m has velocity < -3.5 10 5 , -4.2 10 5 , 0 >m/s. (a) What is the magnetic field due to the wire at the location of the electron? = < 0 0 , 0 0 , 5.6667e-4 0.000567 > tesla (b) What is the magnetic force on the electron due to the current in the wire? = < 3.808e-17 3.81e-17 , -3.1734e-17 -3.17e-17 , 0 0 > N (c) If the moving particle were a proton instead of an electron, what would the magnetic force on the proton be? = < -3.808e-17 -3.81e-17 , 3.1734e-17 3.17e-17 , 0 0 > N 2. 2/2 points | 2/4 submissions Last Response | Show Details A wire is oriented along the x-axis. It is connected to two batteries, and a conventional current of 1.9 A runs through the wire, in the +x direction. Along 0.21 m of the length of

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Ch 20 hw 2 - 1[MI02 20.P.00a 9/9 points | 4/4 submissions...

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