Ch 20 hw 3

# Ch 20 hw 3 - =< 0 0-160000-1.60e 05> N/C 2 2/2 points |...

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1. 9/9 points | 4/4 submissions Last Response | Show Details All Responses Notes An electron travels with velocity < 2 e5, 0, 0> m/s. It enters a region in which there is a uniform magnetic field of < 0, 0.8 , 0> T. What is the magnetic force on the electron? B = < 0 0 , 0 0 , -2.56e-14 -2.56e-14 > N Despite the magnetic force, the electron continues to travel in a straight line at constant speed. You conclude that there must be another force acting on the electron. Since you know there is also an electric field in this region, you decide that the other force must be an electric force. What is this electric force? E = < 0 0 , 0 0 , 2.56e-14 2.56e-14 > N What is the electric field in this region that is responsible for the electric force?
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Unformatted text preview: = < 0 , 0 , -160000-1.60e+05 > N/C 2. 2/2 points | 2/4 submissions Last Response | Show Details All Responses Notes A proton traveling with speed 4 10 5 m/s in the +z direction passes through a region in which there is a uniform magnetic field of magnitude 0.6 T in the +x direction. You want to keep the proton traveling in a straight line at constant speed. To do this, you can turn on an apparatus that can create a uniform electric field throughout the region. What electric field should you apply? magnitude: | | = 240000 2.40e+05 V/m direction: -y-y...
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