Ch 17 hw 2

# Ch 17 hw 2 - 1. -/12 points | 2/4 submissions Last Response...

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1. --/12 points | 2/4 submissions Last Response | Show Details All Responses Notes At a particular instant, a proton at the origin has velocity < 4 e4, -5 e4,0> m/s. You need to calculate the magnetic field at location < 0.03 , 0.05 , 0 > m, due to the moving proton. What is the vector ? = < 0.03 [0.03] , 0.05 [0.05] , 0 [0] >m What is the unit vector ? = < 0.5144957554 [0.514] , 0.8574929257 [0.857] , 0 [0] > What is x ? x = < 0 [0] , 0 [0] , 60024.5048 [60000] > m/s What is the magnetic field at the observation location, due to the moving proton? = < 0 [0] , 0 [0] , 2.82468e-19 [2.82e-19] >T 2. [MI02 17.RQ.02.] --/6 points | 4/4 submissions Last Response | View Saved Work | Show Details All Responses Notes An electron is moving horizontally to the right with speed 6 10 6 m/s. What is the magnetic field due to this moving electron at the indicated locations in Figure 17.60? (Each location is 5 cm from the electron.) Give both magnitude and direction of the magnetic field at each location. Figure 17.60

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## This note was uploaded on 03/31/2008 for the course PY 208M taught by Professor Chabay during the Spring '08 term at N.C. State.

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Ch 17 hw 2 - 1. -/12 points | 2/4 submissions Last Response...

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