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Unformatted text preview: | Show Details All Responses Notes Suppose a wire leads into another, thinner wire of the same material which has only a fourth the cross sectional area. In the "steady state," the number of electrons per second flowing through the thick wire must be equal to the number of electrons per second flowing through the thin wire. If the electric field E 1 in the thick wire is 12 10-3 N/C, what is the electric field E 2 in the thinner wire? E 2 = 0.048 0.048 N/C 4. 2/2 points | 1/4 submissions Last Response | Show Details All Responses Notes Suppose wire A and wire B are made of different metals, and are subjected to the same electric field in two different circuits. Wire B has 4 times the cross-sectional area, 1.6 times as many mobile electrons per cubic centimeter, and 4 times the mobility of wire A. In the steady state, 1 10 18 electrons enter wire A every second. How many electrons enter wire B every second? 2.56e19 2.56e+19 electrons/second...
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- Spring '08