160353_TA3.pdf - Theoretical Assignment 3 Kunal Suryawanshi...

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Theoretical Assignment 3 Kunal Suryawanshi Roll No: 160353 April 12, 2018 1 Question 1 2 Question 2 2.1 Part 1 //Initilation index=0 for all(v V) mark[v]=”unvisited” T=Φ choose(s) //start vertex DFS(s, G) DFS(v, G) mark[v]=”visited” for all(w ADG g (v) ) if(mark[w]=”visited) //found cycle stop; if(mark[w]=”unvisited”) T=T (v,w) DFS(w,G) 2.2 Part 2 If Graph is not cyclic then:- It is not cyclic It is connected For checking connected: Keep a count of number of node visited. If count = n. Then connected. 1
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3 Question 3 Path length can be calculated by forming a graph in which edges are words of dictionary. Every two words which differ by one word (second word can be formed by one insertion, deletion or replacement). After forming graph use BFS or DFS to find minimum length. D=(abc, bcd, acd, abd, bca, bac) A= abc B= bcd abc bac abd acd bcd bca struct Queue word length Queue Dic // insert all element of dictionary in Queue Queue temp while(Dic != is Empty) current = temp.front pointer = Dic.front while(Dic do not end)
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