Chem152_4-Thermo2_Report_110515.xlsx - Name ID Number Quiz...

This preview shows page 1 - 3 out of 4 pages.

Page 1 of 4 Name: Quiz Section: AC ID Number: Lab Partner: Total Points = 60 (10 notebook, 50 template) DATA AND CALCULATIONS data entry 4 pts Preparation of Standards DATA 50 mL of each standard solution (from prelab) Solution Intensity Standard mL of stock Standard 1 7.50E-05 86 1 7.50 E-5 0.75 Standard 2 1.50E-04 174 2 1.50 E-4 1.50 Standard 3 2.25E-04 271 3 2.25 E-4 2.25 Standard 4 3.00E-04 310 4 3.00 E-4 3.00 Standard 5 3.75E-04 379 5 3.75 E-4 3.75 Intensity 22.7 331 4 pts slope 9.63E+05 y-intercept 27.4 Dilution factor 22.7 3.154E-04 2,500 0.788 2 pts A. Standardization of NaOH Run 1 Run 2 Run 3** Mass of KHP, g 0.139 0.136 Molar Mass of KHP, g/mol 204.22 204.22 204.22 Moles KHP 0.00064 0.00067 Initial buret volume, mL 0.29 0.25 Final buret volume, mL 7.85 8.15 Volume NaOH titrated, mL 7.56 7.9 Volume NaOH titrated, L 7.56E-03 7.90E-03 [NaOH], moles/L 0.085 0.084 Average, [NaOH] 0.085 M Part I. Flame emission determination of [K + ] in the 0.50 M KCl + KHP (sat) solution Table 1 : Volume of 5.00x10 -3 M needed to make Table 2 : Flame Photometer Data [K + ], (M) [K + ], (M) Temperature, o C KHP(sat) in 0.50 M KCl M -1 Table 3 : Flame Emission Determination of [K + ] in the original sample Temperature, o C [K ] in Measured Solution (M) [K + ] in Original Solution (M) Part II. Determination of [HP - ] in Saturated KHP Solutions Table 4: NaOH Standardization Chem 152 Experiment #4: Thermodynamics II The Temperature Dependence of the Solubility Product (K sp ) By signing below, you certify that you have not falsified data, that you have not plagiarized any part of this lab report, and that all calculations and responses other than the reporting of raw data are your own independent work. Failure to sign this declaration will result in 5 points being deducted from your report score. Signature: Note: All sections of this report must be typed Type the calculation you used to determine [K+] in the measured and original solutions above. Intensity = 962667*([K+]) + 27.4 From measured (diluted) solution: 331 = 962667*([K+]) + 27.4 [K+] = 3.154E-4M [K+] in original solution = 3.154E-4M *2500 = 0.788M Place your calibration plot (intensity vs. concentration of K + ) here. Make your plot big enough to cover this instruction box so that it is large enought for someone else to read. Add a Trendline and Trendline Eqn and on your plot and be sure to include titles for the plot and each axis. 5.00E-05 1.00E-04 1.50E-04 2.00E-04 2.50E-04 3.00E-04 3.50E-04 4.00E-04 0 50 100 150 200 250 300 350 400 f(x) = 962666.666666667 x + 27.3999999999999 Intensity vs. Concentration of K+ [K+] (M) Intensity
Image of page 1

Subscribe to view the full document.

Page 2 of 4 3 pts B. Titrations of KHP Samples With and Without KCl mL of KHP(aq) used in titrations of Solutions #1-6 1.00 mL
Image of page 2
Image of page 3

{[ snackBarMessage ]}

What students are saying

  • Left Quote Icon

    As a current student on this bumpy collegiate pathway, I stumbled upon Course Hero, where I can find study resources for nearly all my courses, get online help from tutors 24/7, and even share my old projects, papers, and lecture notes with other students.

    Student Picture

    Kiran Temple University Fox School of Business ‘17, Course Hero Intern

  • Left Quote Icon

    I cannot even describe how much Course Hero helped me this summer. It’s truly become something I can always rely on and help me. In the end, I was not only able to survive summer classes, but I was able to thrive thanks to Course Hero.

    Student Picture

    Dana University of Pennsylvania ‘17, Course Hero Intern

  • Left Quote Icon

    The ability to access any university’s resources through Course Hero proved invaluable in my case. I was behind on Tulane coursework and actually used UCLA’s materials to help me move forward and get everything together on time.

    Student Picture

    Jill Tulane University ‘16, Course Hero Intern