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Unformatted text preview: * Empirical Formula Cinnamon contains cam cinnamaldehyde. It contains \$1. 79% C, 6. 10 %. H. and 12. 11 1 0 . Determine the Empirical formula . CqHBO carbon: 81.79 gl x 1 mel - 6.810 0mol C 4. 810 - 9.00= Xq 12.0/ ge 6. 756 Hydrogen : 6.10# 94 x 1 mal - 6.051 mol Hy 6051 = 8.00 =)+8 1.108 get 6 .756 Oxygen : 12. 11 8 9 0 x 1 mol = 0.756 0. 750 - 1 = 0 16.00 90 0:756 * Empirical Formula - Molecular Formula A molecule of nicotine contains 74.0 1 6, 8.65 % H, and 17. 35% N. The molecular mass of nicotine is 162. 26 9/ mole Determine the E.P. 3 MiF. of nicotine ( 65 HIN Carbon : 74.0 ge x I mole 12.01 90 6 . 161 = &gt; 6 . 161 - 4. 96 = ) 65 mole 1.24 Hydrogen : 8.45 ght x I malt! 1. 008 git Mol H 7 8 5 81 = 6.92 = &gt; Hy Nitrogen : 17.35 gx x I moll. 14.01 gy MOIN 1.24 2 81.24 - 1= N 1:24 E.F . mass Molar mass -gland = 2 = ( ( 5H, N) 2 = CioHyNZ 81.11 9 / mel Molecular formula = Clotin NZ (SHIN 5 x ( 12 . 01 ) + 7 x ( 1 . 0 08 ) + 1 x ( 14 . 01 ) = Sloll gl mol...
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• Fall '08
• Staff
• Atom, Mole, Molecular formula, Molecule, Atomic mass unit

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