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Unformatted text preview: 5 d) Plotting directly on a map we have C A B D 1 1 1 1 1 1 The map reduces to B H C + D L . e) For this expression, there is a mixture of sum and product terms, so we will have to use algebra before using any mapping technique. The first term reduces to B + C êê because the third term is redundant. Multiplying out the remaining terms and canceling the common factors using B B êê = 0 and B B = 1 we have H B + C êê L H B C + A B êê + A C L = B B C + A B B êê + A B C + B C C êê + A B êê C êê + A C C êê = BC + A B C + A B êê C êê . The middle term A B C is redundant with respect to the first term B C so that the final expression is B C + A B êê C êê . Note that whenever you have "mixed" expressions, you must manipulate the expression into either an POS or SOP form to apply mapping techniques. F = A êê BC + B êê C êê + A B êê = H A + B êê + C êê L êêêêêêêêêêêêêêêêê + H B + C L êêêêêêêêêê + H A êê + B L êêêêêêêêêê Problem 2.8 Solution a) For this expression, we apply DeMorgan's to each term separately ....
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This note was uploaded on 05/28/2009 for the course ECE ece 25 taught by Professor Bill lin during the Fall '08 term at UCSD.
- Fall '08
- bill lin