hw3_solutions - 20 = s V(kV 6 6 1 10 2 10 5 × × = j Z Ω...

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ECE 320: Energy Conversion and Power Electronics Name: Spring 2009 Homework #3 (Due: Monday, February 23, 2009) Circle or box your answer (don’t forget units). Staple any additional paper used to arrive at your answers to this sheet. 1. For the system shown below, calculate the currents 1 ˆ I and 2 ˆ I . (Hint: refer everything to one side).
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Unformatted text preview: 20 = s V (kV) 6 6 1 10 2 10 5 × + × = j Z ( Ω ) 3 3 2 10 3 10 1 × + × = j Z ( Ω ) I 1 20 : 500 I 2 300 : 10 Z 1 Z 2 V s 2. Problem 2.15 from the course textbook (your sketch should be in the form of Figure 14 of the class handout notes). 3. Problem 2.21 from the course textbook....
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This note was uploaded on 05/30/2009 for the course ECE ECE 320 taught by Professor Timhogan during the Spring '09 term at Michigan State University.

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hw3_solutions - 20 = s V(kV 6 6 1 10 2 10 5 × × = j Z Ω...

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