5 - CHEM 6BL PRELAB/POSTLAB ANSWER KEY EXPERIMENT #5:...

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Dr. S. Berniolles, Page 1 of 3 CHEM 6BL PRELAB/POSTLAB ANSWER KEY EXPERIMENT #5: SEMIMICRO QUALITATIVE ANALYSIS PRELAB ANSWER KEY 1. (0 point) See MSDS Information. 2. (0 point) See MSDS Information. 3. (2 points) Cl - OH NH 4 OH CO 3 2- H 2 S S 2- Ag + Insol/Prec Insol/Prec Soluble Insol/Prec Insol/Prec Insol/Prec Hg 2 2+ Insol/Prec Insol/Prec Insol/Prec Insol/Prec Insol/Prec Insol/Prec Cu 2+ Soluble Insol/Prec Soluble Insol/Prec Insol/Prec Insol/Prec Bi 3+ Soluble Insol/Prec Insol/Prec Insol/Prec Insol/Prec Insol/Prec Sn 4+ Soluble Insol/Prec Insol/Prec Insol/Prec Insol/Prec Insol/Prec Fe 3+ Soluble Insol/Prec Insol/Prec Insol/Prec Sl. soluble Insol/Prec Mn 2+ Soluble Insol/Prec Insol/Prec Insol/Prec Sl. soluble Insol/Prec Zn 2+ Soluble Insol/Prec Soluble Insol/Prec Sl. soluble Insol/Prec Ni 2+ Soluble Insol/Prec Soluble Insol/Prec Sl. soluble Insol/Prec Cr 3+ Soluble Insol/Prec Insol/Prec Insol/Prec Sl. soluble Insol/Prec 4. (1 point) H 2 S is a weak acid. Consequently, the following reactions lie far to the left : H 2 S HS + H + HS S 2– + H + The result is that the concentration of sulfide ion is small when H 2 S is used (H 2 S is a weak acid). Making the solution
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This note was uploaded on 05/31/2009 for the course CHEM 6BL taught by Professor Berniolles during the Spring '08 term at UCSD.

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5 - CHEM 6BL PRELAB/POSTLAB ANSWER KEY EXPERIMENT #5:...

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