09.17b - Oxidation/Reduction Rxns K2Cr2O7 + CH3CH2OH +...

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1 Oxidation/Reduction Rxns K 2 Cr 2 O 7 + CH 3 CH 2 OH + H 2 SO 4 ---> Cr 2 (SO 4 ) 3 + H 2 O + K 2 SO 4 + CH 3 CO 2 H How to Balance? Keep Track of Electrons Oxidation/Reduction Rxns K 2 Cr 2 O 7 + CH 3 CH 2 OH + H 2 SO 4 ---> Cr 2 (SO 4 ) 3 + H 2 O + K 2 SO 4 + CH 3 CO 2 H K +1, O -2, -> Cr +6 to be neutral SO 4 -2, -> Cr +3 to be neutral Gains e _ ! Cr is reduced Reduction and Oxidation Partners required!
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2 Oxidation/Reduction Rxns K 2 Cr 2 O 7 + CH 3 CH 2 OH + H 2 SO 4 ---> Cr 2 (SO 4 ) 3 + H 2 O + K 2 SO 4 + CH 3 CO 2 H Cr(VI) ---> Cr(III) , total of six electrons/mol. From where? H +1, O -2 ---> C’s -4 H +1, O -2 ---> C’s 0 Carbons lose 4 e’s/mol Ethanol is oxidized Oxidation/Reduction Rxns K 2 Cr 2 O 7 + CH 3 CH 2 OH + H 2 SO 4 ---> Cr 2 (SO 4 ) 3 + H 2 O + K 2 SO 4 + CH 3 CO 2 H Cr(VI) ---> Cr(III), gain six electrons/mol. CH
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This note was uploaded on 05/31/2009 for the course CHEM 21L taught by Professor Roy during the Fall '08 term at Duke.

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09.17b - Oxidation/Reduction Rxns K2Cr2O7 + CH3CH2OH +...

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