Example1MFinal1

Example1MFinal1 - Chem 1M Final Exam Name_ TA name_ Section...

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λ ν hc hc = = - = - = 2 i 2 f H i f photon n 1 n 1 R E E E Chem 1M Final Exam Name____________________________________ TA name_________________________________ Section time______________________________ Multiple Choice: Please choose one answer only for each of the following. Experiment 1: Pipet Calibration 1. In the pipet calibration experiment, the mass of water transferred to the beaker was different than the mass of the water weighed. What caused the difference? a. The temperature of the water changed b. Fingerprints on the beaker significantly changed the mass c. Water evaporated from the beaker d. The beaker absorbed water 2. What type of error is mass difference described in the previous question? a. random b. systematic c. human d. instrumental 3. How would your calculated volume be affected if you didn’t account for this mass difference (V=m/ ρ )? a. volume would be too high b. volume would be too low c. no change (effect is cancelled out) d. there is no way to determine this Experiment 2: Density Determination by Three Methods The following volume data was measured by water displacement for a 218.4453 ± 0.0001 g metal cylinder. 4. What is the average volume of the cylinder? a. 24.537 mL b. 24.54 mL c. 24.5 mL d. 25 mL 5. What is the standard deviation in the average volume of the metal cylinder? a. 0.0569 mL b. 0.057 mL c. 0.06 mL d. 0.1 mL 6. When the student calculates the density of the metal cylinder, s/he accidentally used a mass of 228.84452 g. Recall density = mass/volume. Will the calculated density be: a. too high? b. too low? c. unaffected? d. reported with the wrong units? Experiment 8: Hydrogen atom emission 7. Calculate the energy of the photon emitted for the lowest energy state transition in the Paschen series (n f = 3). R H = 2.180 × 10 -18 J h = 6.626 × 10 -34 J . s c = 3.0 × 10 8 m/s a. 1.060 × 10 -19 J b. 3.028 × 10 -19 J c. 1.550 × 10 +19 J d. 1875 J Trial Volume (mL) 1 24.52 2 24.49 3 24.60 ( 29 n x x x x n 2 1 + + + = ( 29 ( 29 ( 29 1 - n x - x x - x x - x 2 n 2 2 2 1 + + + = σ
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8. One of the emission lines in the Balmer (n f = 2) series occurs at 486.1 nm. What is the E (E f – E
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This note was uploaded on 06/01/2009 for the course BIOE 115 taught by Professor Lee during the Spring '09 term at UCSC.

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Example1MFinal1 - Chem 1M Final Exam Name_ TA name_ Section...

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