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# solution_pdf - tokarski(at23678 Angular momentum...

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tokarski (at23678) – Angular momentum – Morozova – (11104) 2 and solving for θ , gives θ = cos 1 bracketleftBigg vector A · vector B A B bracketrightBigg = cos 1 bracketleftbigg ( 5) (2 . 23607) (7 . 07107) bracketrightbigg = 1 . 89255 rad = 108 . 435 . 005 10.0 points A ball having mass 3 . 4 kg is fastened at the end of a flagpole that is connected to the side of a tall building at point P . The length of the flagpole is 4 . 6 m, and it makes an angle 1 . 0472 rad (60 ) with the horizontal. The acceleration of gravity is 9 . 8 m / s 2 . If the ball becomes loose and starts to fall, determine the magnitude of its angular mo- mentum after 38 s about P . Neglect air resis- tance. Correct answer: 2912 . 17. Explanation: Basic Concepts: vector L = vectorr × ( mvectorv ) . The vector from P to the falling ball is vectorr = l cos θ ˆ ı + l sin θ ˆ 1 2 g t 2 ˆ Its velocity is vectorv = gt ˆ . So, vector L = vectorr × ( mvectorv ) = m ( l cos( θ ) ˆ ı + l sin( θ ) ˆ 1 2 g t 2 ˆ × ( g t ˆ ) = m l g t cos( θ ) ˆ k = (3 . 4 kg) (4 . 6 m) (9 . 8 m / s 2 ) (38 s) × cos(1 . 0472 rad) ˆ k = 2912 . 17 kg m 2 / s 2 ˆ k .
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