4BST2_041140597_TMA-2.docx - BBM 203/05 BUSINESS STATISTICS TMA 2 Date of submission Name IC no Student ID H/P no Tutorial Tutor On date Late KHOR HAO

4BST2_041140597_TMA-2.docx - BBM 203/05 BUSINESS STATISTICS...

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BBM 203/05 BUSINESS STATISTICS TMA 2 Date of submission [ ] On date [ ] Late Name KHOR HAO YUN IC no. 941222-07-5556 Student ID 041140597 H/P no. 017-4488422 Tutorial 4 BST 2 Tutor MR. BARATH MUNIANDY
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Question 1 a) Population, n = 6 Samples in a group, r = 3 Number of ways to select 6 C 3 = 6 ! 3 ! ( 6 3 ) ! = 20 b) Sample Branches Total Weekly Expenditure Mean 1 KPI 9000 3000 2 KPA 9000 3000 3 KPJ 10000 3333.3 4 KPS 10000 3333.3 5 KIA 8000 2666.7 6 KIJ 9000 3000 7 KIS 9000 3000 8 KAJ 9000 3000 9 KAS 9000 3000 10 KJS 10000 3333.3 11 PIA 7000 2333.3 12 PIJ 8000 2666.7 13 PIS 8000 2666.7 14 PAJ 8000 2666.7 15 PAS 8000 2666.7 16 PJS 9000 3000 17 IAJ 7000 2333.3 18 IAS 7000 2333.3 19 IJS 8000 2666.7 20 AJS 8000 2666.7 Mean, ´ X Frequency Probability, P( ´ X ) 2333.3 3 3 20 2666.7 7 7 20 3000.0 7 7 20
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3333.3 3 3 20 Total 20 1 c ) Mean of the sampling distribution of mean, μ ´ x = ´ x P ( ´ x ) = 2333.3 ( 3 20 ¿ + 2666.7 ( 7 20 ¿ + 3000.0 ( 7 20 ¿ + 3333.3 ( 3 20 ¿ = 2833.3 d) Variance of sampling distribution of mean, σ 2 ´ x = ´ x ¿ - μ ´ x ¿ 2 P ( ´ x ) Population mean, μ = 2333.3 + 2666.7 + 3000.0 + 3333.3 4 = 2833.3 x f (x - μ) 2 P(x) xP(x) (x - μ) 2 P(x) 2333.3 3 250,000 0.15 350 37,500 2666.7 7 27,755.6 0.35 933 9,714 3000.0 7 27,788.9 0.35 1050 9,726 3333.3 3 250,000 0.15 500 37,500 Total 20 555,544.5 1 2833 94,440 σ 2 = 94,440 Standard Deviation of sampling distribution of mean = σ = 307 e) Standard Error of Mean, σ ´ x Variance of sample variance, σ 2 ´ x = σ 2 n ( N n N 1 ¿ = 94,440 3 ( 6 3 6 1 ¿ = 18,888 Standard Error = 137
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Question 2 a) Sample mean, ´ x = 30
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