4BST2_041140597_TMA-2.docx - BBM 203/05 BUSINESS STATISTICS TMA 2 Date of submission Name IC no Student ID H/P no Tutorial Tutor On date Late KHOR HAO

# 4BST2_041140597_TMA-2.docx - BBM 203/05 BUSINESS STATISTICS...

• Essay
• 10

This preview shows page 1 - 5 out of 10 pages.

BBM 203/05 BUSINESS STATISTICS TMA 2 Date of submission [ ] On date [ ] Late Name KHOR HAO YUN IC no. 941222-07-5556 Student ID 041140597 H/P no. 017-4488422 Tutorial 4 BST 2 Tutor MR. BARATH MUNIANDY

Subscribe to view the full document.

Question 1 a) Population, n = 6 Samples in a group, r = 3 Number of ways to select 6 C 3 = 6 ! 3 ! ( 6 3 ) ! = 20 b) Sample Branches Total Weekly Expenditure Mean 1 KPI 9000 3000 2 KPA 9000 3000 3 KPJ 10000 3333.3 4 KPS 10000 3333.3 5 KIA 8000 2666.7 6 KIJ 9000 3000 7 KIS 9000 3000 8 KAJ 9000 3000 9 KAS 9000 3000 10 KJS 10000 3333.3 11 PIA 7000 2333.3 12 PIJ 8000 2666.7 13 PIS 8000 2666.7 14 PAJ 8000 2666.7 15 PAS 8000 2666.7 16 PJS 9000 3000 17 IAJ 7000 2333.3 18 IAS 7000 2333.3 19 IJS 8000 2666.7 20 AJS 8000 2666.7 Mean, ´ X Frequency Probability, P( ´ X ) 2333.3 3 3 20 2666.7 7 7 20 3000.0 7 7 20
3333.3 3 3 20 Total 20 1 c ) Mean of the sampling distribution of mean, μ ´ x = ´ x P ( ´ x ) = 2333.3 ( 3 20 ¿ + 2666.7 ( 7 20 ¿ + 3000.0 ( 7 20 ¿ + 3333.3 ( 3 20 ¿ = 2833.3 d) Variance of sampling distribution of mean, σ 2 ´ x = ´ x ¿ - μ ´ x ¿ 2 P ( ´ x ) Population mean, μ = 2333.3 + 2666.7 + 3000.0 + 3333.3 4 = 2833.3 x f (x - μ) 2 P(x) xP(x) (x - μ) 2 P(x) 2333.3 3 250,000 0.15 350 37,500 2666.7 7 27,755.6 0.35 933 9,714 3000.0 7 27,788.9 0.35 1050 9,726 3333.3 3 250,000 0.15 500 37,500 Total 20 555,544.5 1 2833 94,440 σ 2 = 94,440 Standard Deviation of sampling distribution of mean = σ = 307 e) Standard Error of Mean, σ ´ x Variance of sample variance, σ 2 ´ x = σ 2 n ( N n N 1 ¿ = 94,440 3 ( 6 3 6 1 ¿ = 18,888 Standard Error = 137

Subscribe to view the full document.

Question 2 a) Sample mean, ´ x = 30

### What students are saying

• As a current student on this bumpy collegiate pathway, I stumbled upon Course Hero, where I can find study resources for nearly all my courses, get online help from tutors 24/7, and even share my old projects, papers, and lecture notes with other students.

Kiran Temple University Fox School of Business ‘17, Course Hero Intern

• I cannot even describe how much Course Hero helped me this summer. It’s truly become something I can always rely on and help me. In the end, I was not only able to survive summer classes, but I was able to thrive thanks to Course Hero.

Dana University of Pennsylvania ‘17, Course Hero Intern

• The ability to access any university’s resources through Course Hero proved invaluable in my case. I was behind on Tulane coursework and actually used UCLA’s materials to help me move forward and get everything together on time.

Jill Tulane University ‘16, Course Hero Intern

Ask Expert Tutors You can ask 0 bonus questions You can ask 0 questions (0 expire soon) You can ask 0 questions (will expire )
Answers in as fast as 15 minutes